删除特定行，所有值匹配

Question

说我有一个表

SELECT * INTO MyTable FROM (
    VALUES ('col1_a', 'col2_a', 'col3_a', 'coln_a'), 
     ('col1_b', 'col2_b', 'col3_b', 'coln_b'), 
     ('col1_c', 'col2_c', 'col3_c', 'coln_c') 
) t (col1, col2, col3, coln) 

我只想删除与每一个列值相匹配的行我的具体（考虑行高度相似只有一个或两列不同）

我当然可以写

DELETE MyTable WHERE col1='col1_a' AND col2='col2_a' AND col3='col3_a' AND coln='coln_a' 
DELETE MyTable WHERE col1='col1_b' AND col2='col2_b' AND col3='col3_b' AND coln='coln_b' 

但是那太烦人了。我想知道是否可以通过简单列出值来方便地编写它？我试过这个

DELETE MyTable FROM (
    VALUES ('col1_a', 'col2_a', 'col3_a', 'coln_a'), 
     ('col1_b', 'col2_b', 'col3_b', 'coln_b') 
) t (col1, col2, col3, coln) 

但这只是删除了MyTable中的所有行，请帮忙。

Answer 1

您可以在DELETE语句中使用INNER JOIN：

DELETE t1 
FROM MyTable t1 
INNER JOIN (
    SELECT * 
    FROM (VALUES 
     ('col1_a', 'col2_a', 'col3_a', 'coln_a'), 
     ('col1_b', 'col2_b', 'col3_b', 'coln_b') 
    )AS a(col1, col2, col3, coln) 
) t2 
    ON t2.col1 = t1.col1 
    AND t2.col2 = t1.col2 
    AND t2.col3 = t1.col3 

---

正如评论说Frisbee，你可以删除SELECT *：

DELETE t1 
FROM MyTable t1 
INNER JOIN (
    VALUES 
     ('col1_a', 'col2_a', 'col3_a', 'coln_a'), 
     ('col1_b', 'col2_b', 'col3_b', 'coln_b')  
) AS t2(col1, col2, col3, coln) 
    ON t2.col1 = t1.col1 
    AND t2.col2 = t1.col2 
    AND t2.col3 = t1.col3