2010-04-18 61 views
7

我刚刚在virtualenv上设置了一个django应用程序,部署使用结构脚本顺利进行,但现在.wsgi不工作,我试过了互联网上的所有变体,但没有运气。我.wsgi文件是:django + mod_wsgi在virtualenv不起作用

import os 
import sys 
import django.core.handlers.wsgi 

# put the Django project on sys.path 
root_path = os.path.abspath(os.path.dirname(__file__) + '../') 
sys.path.insert(0, os.path.join(root_path, 'kcdf')) 
sys.path.insert(0, root_path) 

os.environ['DJANGO_SETTINGS_MODULE'] = 'kcdf.settings' 

application = django.core.handlers.wsgi.WSGIHandler() 

我不断收到同样的错误:

[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] mod_wsgi (pid=16938): Exception occurred processing WSGI script '/home/kcdfweb/webapps/kcdf.web/releases/current/kcdf/apache/kcdf.wsgi'. 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] Traceback (most recent call last): 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 230, in __call__ 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]  self.load_middleware() 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 33, in load_middleware 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]  for middleware_path in settings.MIDDLEWARE_CLASSES: 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 269, in __getattr__ 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]  self._setup() 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 40, in _setup 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]  self._wrapped = Settings(settings_module) 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 75, in __init__ 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159]  raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) 
[Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] ImportError: Could not import settings 'kcdf.settings' (Is it on sys.path? Does it have syntax errors?): No module named kcdf.settings 

我的虚拟环境是/ home/user中/ webapps /下kcdfweb 我的应用程序是/ home /用户/ webapps中/kcdf.web/releases/current/project_name 我的wsgi文件home/user/webapps/kcdf.web/releases/current/project_name/apache/project_name.wsgi

回答

1

您需要添加两个以上的目录你的wsgi文件,而不是:

root_path = os.path.abspath(os.path.dirname(__file__) + '../') 

你应该有

root_path = os.path.abspath(os.path.join(os.path.dirname(__file__), '../', '../')) 

...作为你的WSGI文件是在一个名为apache目录,你的项目文件夹下。

+0

试过,它没有工作,可能是值得一提的是,当我创建的virtualenv体外的样品Django项目,并试图运行它我得到: jwesonga @ KCDF:〜/ $测试仪出口DJANGO_SETTINGS_MODULE = tester.settings jwesonga @ kcdf:〜/ tester $ django-admin.py runserver 错误:无法导入设置'tester.settings'(它是否在sys.path?是否有语法错误?):没有名为tester.settings的模块 – jwesonga 2010-04-18 14:14:47

0

如果您使用的是virtualenv,则需要在WSGI脚本中激活它才能正确设置路径。

root_path = os.path.abspath(os.path.dirname(__file__) + '../') 
activate_this = os.path.join(root_path, "bin/activate_this.py") 
execfile(activate_this, dict(__file__=activate_this)) 
+1

不鼓励在mod_wsgi中使用activate_this.py,因为它确实会在sys.prefix中弄乱,这在技术上可能会导致某些代码出现问题。阅读'http://code.google.com/p/modwsgi/wiki/VirtualEnvironments'。 – 2010-04-18 22:45:24

+0

另外,activate_this是不必要的。你真正需要做的就是在virtualenv网站包目录上调用site.addsitedir()。 – 2010-04-19 13:25:53

+3

不,site.addsitedir()并不总是足够的,特别是如果您在创建虚拟环境时未使用--no-site-packages。这是因为site.addsitedir()在sys.path的末尾添加了新目录,因此标准Python安装中的任何内容仍然优先。该脚本的目的是对sys.path重新排序,以便新的目录在开始时优先。请阅读mod_wsgi网站上提到的文档。 – 2010-04-19 22:51:28

0

您的“kcdf”目录中是否有__init__.py文件?没有这个你的设置文件不能被导入。

另外,如果您希望能够从virtualenv中导入内容,您应该在virtualenv的site-packages目录上调用site.addsitedir()。详情请参阅the mod_wsgi docs。虽然如果它甚至不能导入你的设置,我不认为这是你目前的问题。

7

我建议你看看docs与mod_wsgi一起使用Virtualenv。他们提供了一些替代方法来连接你的virtualenv,这可能对你更好。