Question

我有2个字符串是这样的：

$post_des = 'Neque porro quisquam est qui do <a href = "http://example.com/lorem_ipsum"> lorem ipsum </a> quia dolor sit amet, consectetur, adipisci velit...'; 

$post_detail = '<a href = "http://example.com/lorem_ipsum">lorem ipsum </a> dolor sit amet, consectetur adipiscing elit. Donec quis purus finibus, ultricies diam at, faucibus nunc. Donec ac luctus ipsum,vitae <a href = "http://example.com/vehicula"> vehicula </a> erat. ' ; 

，并希望删除所有重复AHREF标签，就像这样：

$post_des = 'Neque porro quisquam est qui do <a href = "http://example.com/lorem_ipsum"> lorem ipsum </a> quia dolor sit amet, consectetur, adipisci velit...'; 

$post_detail = 'lorem ipsum dolor sit amet, consectetur adipiscing elit. Donec quis purus finibus, ultricies diam at, faucibus nunc. Donec ac luctus ipsum,vitae <a href = "http://example.com/vehicula"> vehicula </a> erat. ' ; 

我试图用DOM文档和in_array，但还有约2百万个标签（ex lorem ipsum，vehicular）。有没有更简单的方法？

Answer 1

使用preg_match获取所有链接标记出现并迭代它们以删除（替换为空字符串）$ post_detail。 [小提琴] [1]

if(preg_match('/<a.*\>/',$post_des,$link_tags)) 
{ 
    foreach($link_tags as $link_tag) 
    { 
     preg_match('#<a[^>]+>(.+?)</a>#ims', $link_tag,$str); 

     $post_detail = str_replace($link_tag,@$str[1],$post_detail); 
    } 
} 

http://viper-7.com/Ul8BBN