如何高效地返回WHERE条件的行与多组值匹配？

Question

我有下面的表：

id, name, surname 

我有以下SQL查询：

SELECT `id` from `table` WHERE name = 'John' AND surname = 'Smith'; 

正如我有名字和姓氏的列表，我想检查，如果他们是否存在于表中或者我不想做单个查询并返回id（如果存在匹配集合的姓名和姓）或空的id（或零）以指示不匹配名字和姓氏的结合。

所以我也基本是这样的：

SELECT `id` from `table` WHERE name = 'John' AND surname = 'Smith'; 
SELECT `id` from `table` WHERE name = 'Claudia' AND surname = 'Janssen'; 
SELECT `id` from `table` WHERE name = 'Eduart' AND surname = 'Allen'; 
SELECT `id` from `table` WHERE name = 'Don' AND surname = 'Diablo'; 
SELECT `id` from `table` WHERE name = 'Esther' AND surname = 'Smith'; 

（大量的查询）

我觉得在声明中不起作用，因为它还会如果返回一个ID有人用表中找到了同名和另一个姓氏相同的人。找到组合很重要。

我的问题是：如何有效地执行mysql查询，如上面5个单个查询所规定的那样？

Answer 1

您可以使用OR：

SELECT id 
FROM table 
WHERE (name = 'John' and surname 'Smith') 
OR (name = 'Claudia' and surname 'Janssen') 
OR (name = 'Eduart' and surname 'Allen') 
... 

确保您使用括号，因为AND和OR之间的优先级。

你也可以使用UNION，如果你对name和surname列的索引可能更有效，因为OR状况可能不会使用他们去做。

SELECT id from table WHERE name = 'John' and surname 'Smith' 
UNION 
SELECT id from table WHERE name = 'Claudia' and surname 'Janssen' 
UNION 
SELECT id from table WHERE name = 'Eduart' and surname 'Allen' 
UNION 
... 

Answer 2

这是你在找什么？

SELECT `id` 
FROM `table` 
WHERE (`name` = 'John' AND `surname` = 'Smith') 
     OR (`name` = 'Claudia' AND `surname` = 'Janssen') 
     OR (`name` = 'Eduart' AND `surname` = 'Allen') 
     OR (`name` = 'Don' AND `surname` = 'Diablo') 
     OR (`name` = 'Esther' AND `surname` = 'Smith'); 

Answer 3

你也可以尝试以连接两个部分，搜索这样的：

SELECT id, CONCAT_WS(",", surname, name) AS FullName 
FROM table1 
HAVING FullName IN (
    "hand,bob", 
    "smith,steve", 
    "brown,rob", 
    "green,tom" 
) 

OR

SELECT id, CONCAT_WS(",", surname, name) AS FullName 
FROM table1 
WHERE CONCAT_WS(",", surname, name) IN (
    "hand,bob", 
    "smith,steve", 
    "brown,rob", 
    "green,tom" 
) 

工作小提琴：http://sqlfiddle.com/#!2/2463e6