我写了一个非常简单的评论系统的开头。它使用jQuery/AJAX/PHP MySQL。到目前为止它工作正常。但是,一旦提交评论,您必须刷新页面才能显示评论。它如何显示在提交。ajax评论显示在提交w/out页面刷新
我希望这里没有太多的代码,但这里有三个部分。 jQuery/php插入评论查询/ php选择评论查询。
的jQuery/AJAX:
$(document).ready(function() {
$('#button').click(function() {
var name = $('#name').val();
var comment = $('#comment').val();
if(name == '' || comment == '') {
$('#comment_messages').html('Please enter both fields');
} else if(name !== '' || comment !== '') {
$('#comment_messages').html('');
$.ajax({
type: 'POST',
url: 'comments.php',
data: 'name='+name+'&comment='+comment,
success: function(data) {
$('#comments_area').append(data);
}
});
}
});
});
PHP INSERT(插入注释):
<?php
include('init.inc.php');
if(isset($_POST['name'], $_POST['comment'])) {
$name = $_POST['name'];
$comment = $_POST['comment'];
if(!empty($name) && !empty($comment)) {
$query = mysql_query("INSERT INTO comments VALUES(NULL, '$name', '$comment', CURRENT_TIMESTAMP)");
if($query === true) {
// right here is what is being returned to success: function(data) in the ajax script. What's the best way to return the comment here?
} else {
echo 'Hmmm... that\'s odd........';
}
} else {
echo 'Please enter both fields';
}
}
?>
PHP SELECT(检索评论):
<?php
$query = mysql_query("SELECT * FROM comments ORDER BY time DESC LIMIT 10");
$num = mysql_num_rows($query);
if($num >= 1) {
while($fetch = mysql_fetch_assoc($query)) {
$name = $fetch['name'];
$comment = $fetch['comment'];
$time = $fetch['time'];
?>
<div id="user_comments">
<?php echo $name; ?> said at: <span id="time_stamp"><?php echo $time; ?></span><p>- <?php echo $comment; ?>
</div>
<?php
}
}
?>
UPDATE:
个新增两行底部:
$(document).ready(function() {
$('#button').click(function() {
var name = $('#name').val();
var comment = $('#comment').val();
if(name == '' || comment == '') {
$('#comment_messages').html('Please enter both fields');
} else if(name !== '' || comment !== '') {
$('#comment_messages').html('');
$.ajax({
type: 'POST',
url: 'comments.php',
data: 'name='+name+'&comment='+comment,
success: function(data) {
$('#comments_area').append('<b>'+name+'</b><p>- '+comment);
$('#comment_messages').html(data);
}
});
}
});
});
好主意。但是你应该创建SUCCES/FAILURE结构,那么对吗?原因不会成功加载页面,即使注释失败被插入到数据库中? :) –
你应该返回PHP头,如果成功则返回200,如果失败则返回4xx。这样,它不会最终在成功 –
我喜欢这种方法。我还在您建议的代码行下面添加了SUCCESS/FAILURE(成功/失败)(参见更新)。这是可扩展/安全/常见的做法吗?它似乎会在append()标签中变得非常混乱。它似乎有点混乱。 – Graham