Oracle将SQL迁移到ANSI SQL

Question

这是关于将查询转换为ANSI SQL的。我试着用Oracle旧语法编写这个查询，并且抛出了下面的错误，所以我最终改变了它，如下所示。经过研究，我发现ANSI SQL支持这样的要求。

ERROR：表可能是外部联接至多一个其他表提示

这里是我写的这是工作，但是如果有这种可能被改写的方式，将是巨大的，知道查询在ANSI-SQL中或通过使用旧的外部联接语法。我正在寻找联合查询在with子句中被重写为其他人的工作正常。

WITH BOM_PARENT AS (
    SELECT MX.SAP_MATNR MATNR 
     , TRIM(I.IPRODUCTION) IPRODUCTION 
     , TRIM(I.IDRAWING) IDRAWING 
     , TRIM(M.BCHLD) BCHLD 
     , M.BSEQ BSEQ 
     , PX.WERKS WERKS 
     , M.BPSCP MENGE 
     , UX.SAP_UOM MEINS 
     , I.IUMS 
    FROM XX_MAIN.XX_BPCS_IIM I 
     , XX_MAIN.XX_BPCS_MPB M 
     , XX_MAIN.XX_MATER_XREF MX 
     , XX_MAIN.XX_TRUNK_XREF PX 
     , XX_MAIN.XX_MP_UNIT_XREF UX 
    WHERE TRIM(I.IPRODUCTION) = TRIM(M.BPROD) 
     AND TRIM(MX.PROD_MATNR) = TRIM(I.IPRODUCTION) 
     AND MX.CONV_FACTOR = TO_CHAR(I.IUMCN) 
     AND I.IUMS = UX.LEGACY_UOM 
     AND UX.SOURCE = 'AP' 
     AND I.SOURCE = PX.SOURCE 
     AND I.ENTITY = PX.LEGACY_PLANT 
     AND I.ENTITY = 'SG' 
     AND I.IITYP = '4' 
     --AND PX.WERKS IN ('1379') 
     AND MX.SAP_MTART <> 'ZPRD' 
    ) 
    , BOM_CHILDS AS 
    (
    SELECT B.*, 
      X.SAP_MATNR IDNRK 
      , ROW_NUMBER() OVER (PARTITION BY B.MATNR,B.WERKS ORDER BY B.MATNR,B.WERKS) ID_ITEM_NO 
      , X.PROD_MATNR IDNRK_IPRODUCTION 
      , X.DRAWING_MATNR IDNRK_IDRAWING  
     FROM BOM_PARENT B 
      , XX_MAIN.XX_MATER_XREF X 
    WHERE B.BCHLD = TRIM(X.PROD_MATNR) 
     AND X.SAP_MTART <> 'ZPRD' 
     AND X.SOURCE = 'AP' 
    ) 
    SELECT DISTINCT C.MATNR 
     , C.IPRODUCTION 
     , C.IDRAWING 
     , C.WERKS 
     , (C.ID_ITEM_NO*10) ID_ITEM_NO 
     , C.BSEQ 
     , C.IDNRK 
     , C.IDNRK_IPRODUCTION 
     , C.IDNRK_IDRAWING 
     , C.MENGE BPSCP 
     , STPO.MENGE STPO_MENGE 
     , C.MEINS MEINS 
     , C.IUMS IUMS 
     , STPO.MEINS STPO_MEINS 
     FROM BOM_CHILDS C 
     , XX_MAIN.XX_MAST MAST 
     , XX_MAIN.XX_STPO STPO 
     WHERE C.MATNR = MAST.MATNR 
     AND MAST.STLNR = STPO.STLNR 
     AND MAST.STLAN = '1' 
     AND MAST.WERKS = C.WERKS 
     AND STPO.IDNRK = C.IDNRK 
    UNION 
    SELECT DISTINCT C.MATNR 
     , C.IPRODUCTION 
     , C.IDRAWING 
     , C.WERKS 
     , (C.ID_ITEM_NO*10) ID_ITEM_NO 
     , C.BSEQ 
     , C.IDNRK 
     , C.IDNRK_IPRODUCTION 
     , C.IDNRK_IDRAWING 
     , C.MENGE BPSCP 
     , STPO.MENGE STPO_MENGE 
     , C.MEINS MEINS 
     , C.IUMS IUMS 
     , STPO.MEINS STPO_MEINS 
     FROM BOM_CHILDS C 
     , XX_MAIN.XX_MAST MAST 
     , XX_MAIN.XX_STPO STPO 
     WHERE C.MATNR = MAST.MATNR(+) 
     AND MAST.STLNR = STPO.STLNR(+) 
     AND MAST.STLAN(+) = '1' 
     AND MAST.WERKS(+) = C.WERKS 
     AND STPO.IDNRK IS NULL 
    ORDER BY MATNR,WERKS,ID_ITEM_NO,BSEQ; 

Answer 1

这部分可能是造成问题的原因：

FROM BOM_CHILDS C 
    , XX_MAIN.XX_MAST MAST 
    , XX_MAIN.XX_STPO STPO 
    WHERE C.MATNR = MAST.MATNR(+) 
    AND MAST.STLNR = STPO.STLNR(+) 
    AND MAST.STLAN(+) = '1' 
    AND MAST.WERKS(+) = C.WERKS 
    AND STPO.IDNRK IS NULL 

为了使这更容易一点，让我们重新排列WHERE条款下令由表它们之间的关系：

FROM BOM_CHILDS C 
, XX_MAIN.XX_MAST MAST 
, XX_MAIN.XX_STPO STPO 
-- Joining C to MAST 
WHERE C.MATNR = MAST.MATNR(+) 
    AND C.WERKS = MAST.WERKS(+) 
    AND MAST.STLAN(+) = '1' 
-- Joining MAST to STPO 
    AND MAST.STLNR = STPO.STLNR(+) 
    AND STPO.IDNRK IS NULL 

---

我们有C加入MAST使用从MAST它匹配的“驱动程序”表，拿起数据（左连接）：

FROM BOM_CHILDS C 
LEFT JOIN XX_MAIN.XX_MAST MAST 
    ON C.MANTR = MAST.MANTR 
AND C.WERKS = MAST.WERKS 
AND MAST.STLAN = '1' 

然后我们需要添加STPO到联接：

LEFT JOIN XX_MAIN.XX_STPO STPO 
    ON MAST.STLNR = STPO.STLNR 
AND STPO.IDNRK IS NULL 

---

把这一切我们得到：

FROM BOM_CHILDS C 
LEFT JOIN XX_MAIN.XX_MAST MAST 
    ON C.MANTR = MAST.MANTR 
AND C.WERKS = MAST.WERKS 
AND MAST.STLAN = '1' 
LEFT JOIN XX_MAIN.XX_STPO STPO 
    ON MAST.STLNR = STPO.STLNR 
AND STPO.IDNRK IS NULL 

---

也就是说，即使(+)适用于左/右/外部连接，Oracle recommends not using it：

Oracle建议您使用FROM条款OUTER JOIN语法，而不是甲骨文加入经营者。外连接是使用Oracle联接运算符(+)受到以下规则和限制，并不适用于FROM条款OUTER JOIN语法查询：...