如何通过POST请求与Android发送JSON对象

Question

我想构建一个小应用程序，其中应用程序将与JSON对象的帮助下与PHP脚本进行通信。我成功实现了GET请求测试应用程序，但是对帖子使用JSON会产生问题。该代码不会产生错误，但用什么都没有，除了一个空的Array（我的PHP脚本回复）这意味着什么用的代码连接发送：

<?php print_r($_REQUEST); ?> 

与

<?php print($_REQUEST['json']); ?> 

抛出HTML努力回到带有json变量未找到错误的应用程序。

我已经试过这里提到的几个解决方案，包括：How to send a JSON object over Request with Android?和How to send a json object over httpclient request with android所以如果你能指出我的错误并能简要描述我到底做错了什么，那将是非常好的。谢谢。

下面是JSON对象从哪里转换为字符串，然后附加到Post变量的代码片段。

 DefaultHttpClient httpclient = new DefaultHttpClient(); 
     HttpPost httppostreq = new HttpPost(wurl); 
     StringEntity se = new StringEntity(jsonobj.toString()); 
     se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json")); 
     httppostreq.setEntity(se); 
      //httppostreq.setHeader("Accept", "application/json"); 
     //httppostreq.setHeader("Content-type", "application/json"); 
     //httppostreq.setHeader("User-Agent", "android"); 
     HttpResponse httpresponse = httpclient.execute(httppostreq); 
     HttpEntity resultentity = httpresponse.getEntity(); 

这里是Wireshark的，通过收集，如果它可以帮助TCP流转储：

POST /testmysql.php?test=true HTTP/1.1 
Content-Length: 130 
Content-Type: application/json;charset=UTF-8 
Content-Type: application/json;charset=UTF-8 
Host: 192.168.100.4 
Connection: Keep-Alive 
User-Agent: Apache-HttpClient/UNAVAILABLE (java 1.4) 
{"weburl":"hashincludetechnology.com","header":{"devicemodel":"GT-I9100","deviceVersion":"2.3.6","language":"eng"},"key":"value"}HTTP/1.1 200 OK 
Date: Mon, 30 Apr 2012 22:43:10 GMT 
Server: Apache/2.2.17 (Win32) 
Content-Length: 34 
Keep-Alive: timeout=5, max=100 
Connection: Keep-Alive 
Content-Type: text/html 
Array 
(
    [test] => true 
) 
Test // echo statement left intentionally. 

Answer 1

您使用在服务器端PHP

，所以你的HTTP实体必须是一个多编码的一个。请参阅this link。您正在使用字符串实体，但这不正确。它必须是MultipartEntity，它模拟浏览器在网页中提交表单时的功能。 MultipartEntity应该在httpmime jar中。

一旦你有你的多部分实体，只需添加一个名为“json”的零件，并将其内容设置为你的json编码对象的字符串表示。

请注意，这个答案是因为您在服务器端使用PHP，所以您必须使用其“协议”通过$ _REQUEST读取变量。如果你在服务器端使用你自己的请求解析器，即使是一个StringEntity也可以。请参见HTTP_RAW_POST_DATA

Answer 2

下面应该可以工作。确保为您的表单帖子期望的顶部设置适当的键。此外，我还包括如何发送图像以及其他各种json数据，如果没有必要删除这些行。

static private String postToServerHelper(
      String action, 
      JSONObject jsonData, 
      byte[] imageData){ 

     // keys for sending to server 
     /** The key for the data to post to server */ 
     final String KEY_DATA = "data"; 
     /** The key for the action to take on server */ 
     final String KEY_ACTION = "action"; 
     /** The return code for a successful sync with server */ 
     final int GOOD_RETURN_CODE = 200; 
     /** The key for posting the image data */ 
     final String KEY_IMAGE = "imageData"; 
     /** The image type */ 
     final String FILE_TYPE = "image/jpeg"; 
     /** The encoding type of form data */ 
     final Charset ENCODING_TYPE = Charset.forName("UTF-8"); 

     // the file "name" 
     String fileName = "yourFileNameHere"; 

     // initialize result string 
     String result = ""; 

     // initialize http client and post to correct page 
     HttpClient client = new DefaultHttpClient(); 
     HttpPost httpPost = new HttpPost("http://www.yourdomain.com/yourpage.php"); 

     // set to not open tcp connection 
     httpPost.getParams().setBooleanParameter(CoreProtocolPNames.USE_EXPECT_CONTINUE, false); 

     // build the values to post, the action and the form data, and file data (if any) 
     MultipartEntity multipartEntity = new MultipartEntity(
       HttpMultipartMode.BROWSER_COMPATIBLE); 
     try{ 
      multipartEntity.addPart(KEY_ACTION, new StringBody(action, ENCODING_TYPE)); 
      multipartEntity.addPart(KEY_DATA, new StringBody(jsonData.toString(), ENCODING_TYPE)); 
      if (imageData != null){ 
       multipartEntity.addPart(KEY_IMAGE, new ByteArrayBody(imageData, FILE_TYPE, fileName)); 
      } 
     }catch (Exception e){ 
      return e.getMessage(); 
     } 

     // set the values to the post 
     httpPost.setEntity(multipartEntity); 

     int statusCode= -1; 

     // send post 
     try { 
      // actual send 
      HttpResponse response = client.execute(httpPost); 

      // check what kind of return 
      StatusLine statusLine = response.getStatusLine(); 
      statusCode = statusLine.getStatusCode(); 

      // good return 
      if (statusCode == GOOD_RETURN_CODE) { 
       // read return 
       HttpEntity entity = response.getEntity(); 
       InputStream content = entity.getContent(); 
       BufferedReader reader = new BufferedReader(new InputStreamReader(content)); 
       String line; 
       while ((line = reader.readLine()) != null) { 
         builder.append(line + "\n"); 
       } 
       content.close(); 
       result = builder.toString(); 

       // bad return 
      } else { 
       return String.parse(statusCode); 
      } 

      // different failures 
     } catch (ClientProtocolException e) { 
      return e.getMessage(); 
     } catch (IOException e) { 
      return e.getMessage(); 
     } 

     // return the result 
     return result; 
    } 

Answer 3

DefaultHttpClient httpClient = new DefaultHttpClient（）; HttpPost httpPost = new HttpPost（url）;

  JSONObject clientList = new JSONObject(); 
      clientList.put("name",""); 
      clientList.put("email",""); 
      clientList.put("status",""); 
      clientList.put("page",""); 



      JSONObject listclient = new JSONObject(); 
      listclient.put("mydetail", clientList); 

    //--List nameValuePairs = new ArrayList(1); 
      List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); 
      nameValuePairs.add(new BasicNameValuePair("token", tokenid)); 
      nameValuePairs.add(new BasicNameValuePair("json_data", listclient.toString())); 


      httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
      Log.d("JSON",nameValuePairs.toString()); 

      //-- Storing Response 
      HttpResponse httpResponse = httpClient.execute(httpPost);