接收到大多数结果为Define the constructor, homeboy
的此错误。深入了解我所犯的错误,因为我认为它是在我的课堂上定义的。我对Java很新,如果它很明显,不要撕碎我。Java构造函数错误:已定义构造函数,未找到
Error: constructor KServer in class KServer cannot be applied to given types;
KServer server = new KServer(port);
required: no arguments
found: int
reason: actual and formal argument lists differ in length
1 error
KServer.java
public class KServer {
private int port;
//isn't this the constructor defined?
public void KServer(int PORT) {
port = PORT;
}
public void Run() {...}
}
KServ.java
public class KServ {
public static void main(String[] args) {
if (args.length != 1) {
System.err.println("Usage: java KServ <port number>");
System.exit(1);
}
int port = Integer.parseInt(args[0]);
KServer server = new KServer(port);
server.Run();
}
}
从您的“构造函数” – Reimeus
中删除'void'关键字,它必须是noob错误。拉屎。它在技术上不是无效的吗? – Chemistpp
一个构造函数没有返回类型 - 所以我想你的“构造函数”被解释为方法 – Rhayene