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我创建网站菜单&子菜单是&从数据库进行完全动态的有点糊涂了。对于菜单我用列表视图控件这是很好的,现在所有的菜单都有它是基于菜单的子菜单(菜单子),以及。现在我不明白该怎么做。我想使用嵌套的ListView会很好,但我需要一个提示如何绑定嵌套的ListView?绑定列表视图列表视图里面的子菜单(菜单子)
这是我的主要列表视图
<asp:ListView ID="mainMenu" runat="server">
<ItemTemplate>
<li><asp:HyperLink ID="mainLinks" runat="server" NavigateUrl='<%# Eval("name", "~/{0}") %>' Text='<%# Eval("name") %>'></asp:HyperLink>
<ul class="super-child">
<asp:ListView ID="childMenu" runat="server">
<ItemTemplate>
<li><asp:HyperLink ID="cat3" runat="server" NavigateUrl='<%# Eval("category") & Eval("name", "/{0}") %>' Text='<%# Eval("name") %>'></asp:HyperLink></li>
</ItemTemplate>
</asp:ListView>
</ul>
</li>
</ItemTemplate>
</asp:ListView>
Private Sub bigMenu()
Dim constr As String = ConfigurationManager.ConnectionStrings("conio").ConnectionString
Using con As New MySqlConnection(constr)
Using cmd As New MySqlCommand()
cmd.CommandText = "SELECT * FROM mainMenu WHERE status = 'active' order by CAST(position as SIGNED INTEGER) asc"
cmd.Connection = con
Using sda As New MySqlDataAdapter(cmd)
Dim dt As New DataTable()
sda.Fill(dt)
mainMenu.DataSource = dt
mainMenu.DataBind()
End Using
End Using
End Using
End Sub