从同一名称的多个标签中选择<select>

Question

if (fromObject == null) fromObject = primaryTable; 
    var id = fromObject+"_"+toObject; 
    var tr = $('<tr id="'+id+'"></tr>').appendTo($("#joins")); 

    tr.append('<td width=20%><select style="width:100%" type="text" name="from_object" id="from_object" value=""></select></td>'); 
    tr.append('<td width=20%><select style="width:100%" type="text" name="to_object" id="to_object" value=""></select></td>'); 
    tr.append('<td width=20%><input style="width:100%" type="text" name="from_column" id="from_column" value="" readonly></td>'); 
    tr.append('<td width=20%><input style="width:100%" type="text" name="to_column" id="to_column" value="" readonly></td>'); 
    tr.append('<td width=20%><select style="width:100%" type="text" name="join_type" id="join_type" value=""></select></td>'); 


    var combo3 = $("select[name=from_object]"); 

这是我的问题。我经历了多次追加的过程，并留下了许多具有相同名称的选择标签。我想弄清楚如何选择'from_object'。我必须动态地执行此操作吗？现在combo3总是选择第一个标签。

Answer 1

我不完全理解这个问题。为了获得第一次使用

$('select[name=from_object]:first').doWhatever(): 

获得所有使用

$('select[name=from_object]').each(function(){ 
    $(this).doWhatever(); 
}); 

但是从来没有使用相同的ID两次。

Answer 2

您的html无效与这些重复的ID。我试图同时解决你所要求的和重复的ID问题。它应该给你一个解决方案的良好开端，如果不是直接开箱即用。

编辑答案

if (fromObject == null) fromObject = primaryTable; 
    var id = fromObject+"_"+toObject; 
    // don't append to the DOM until the last second, i moved tr.appendTo() to the end 
    var uniqueIdIndex = $("tr[id^='"+id+"_tr'").length +1; // get a unique index 
// the idea of cloning HTML and appending it takes some getting used to, but makes it easy to change and maintain. don't let it throw you 
// all this cloning stuff is to get you some Unique Ids. 
     var masterTR = $('<tr id="'+id+'_tr_'+uniqueIdIndex+'"></tr>'); 
     var masterTD = $('<td width="20%"></td>'); 
     var masterDD = $('<select type="text" style="width:100%"></select>'); 
     var masterCI = $('<input style="width:100%" type="text" value="" readonly></input>'); 
     // grab a default drop down, set the name, ID and value 
     var currentInput = masterDD.clone().attr({"name":"from_object","id": id+"_from_object_"+uniqueIdIndex,"value":""}); 
     var tr = masterTR.clone(); // get a Row 
     tr.append(masterTD.clone().append(currentInput)); // clone a td, append the input, and append that to the row 
     // grab a default drop down, set the name, ID and value 
     currentInput = masterDD.clone().attr({"name":"to_object","id": id+"_to_object_"+uniqueIdIndex,"value":""}); 
     tr.append(masterTD.clone().append(currentInput)); 
     currentInput = masterCI.clone().attr({"name":"from_column","id": id+"_from_column_"+uniqueIdIndex,"value":""}); 
     tr.append(masterTD.clone().append(currentInput)); 
     currentInput = masterCI.clone().attr({"name":"to_column","id": id+"_to_column_"+uniqueIdIndex,"value":""}); 
     tr.append(masterTD.clone().append(currentInput)); 
     currentInput = masterDD.clone().attr({"name":"join_type","id": id+"_join_type_"+uniqueIdIndex,"value":""}); 
     tr.append(masterTD.clone().append(currentInput)); 

      tr.appendTo($("#joins")); 
//optionally, find the most recently added from_column "select[name='from_column']" 
      var combo3 = $("[id^='"+id+"_from_column]", "#joins").filter(":last"); 

旧答案

如果（fromObject == NULL）fromObject = primaryTable; var id = fromObject +“_”+ toObject; var tr = $（''）。appendTo（$（“＃joins”））;

tr.append('<td width=20%><select style="width:100%" type="text" name="from_object" id="'+id+'from_object" value=""></select></td>'); 
    tr.append('<td width=20%><select style="width:100%" type="text" name="to_object" id="'+id+'to_object" value=""></select></td>'); 
    tr.append('<td width=20%><input style="width:100%" type="text" name="from_column" id="'+id+'from_column" value="" readonly></td>'); 
    tr.append('<td width=20%><input style="width:100%" type="text" name="to_column" id="'+id+'to_column" value="" readonly></td>'); 
    tr.append('<td width=20%><select style="width:100%" type="text" name="join_type" id="'+id+'join_type" value=""></select></td>'); 



    var combo3 = $("#"+id+"from_object");