Python代码不能执行代码

Question

我正在使用一个来自Invent的Python程序，龙的领域之一，来创造我自己的故事。出于某种原因，从chooseVillage开始再次播放的代码不起作用。它只是不显示。你能帮我么？提前致谢。

的代码是如repl.it here如下所示

import random 
import time 

def displayIntro(): 
    print('You are in a land full of dragons. In front of you,') 
    print('you see two caves. In one cave, the dragon is friendly') 
    print('and will share his treasure with you. The other dragon') 
    print('is greedy and hungry, and will eat you on sight.') 
    print() 

def chooseCave(): 
    cave = '' 
    while cave != '1' and cave != '2': 
     print('Which cave will you go into? (1 or 2)') 
     cave = input() 

     return cave 

def checkCave(chosenCave): 
    print('You approach the cave...') 
    time.sleep(2) 
    print('It is dark and spoopy...') 
    time.sleep(2) 
    print('A large dragon jumps out in front of you! He looks at you and...') 
    print() 
    time.sleep(2) 

    friendlyCave = random.randint(1,2) 

    if chosenCave == str(friendlyCave): 
     print('Gives you his treasure') 
     print('You decide to spend it at a village') 
    else: 
     print('Gobbles you down in one bite.') 
     quit() 

def chooseVillage(): 
    village = '' 
    while village != '1' and village != '2' and village != '3': 
    print('Which village will you go to? (1, 2, or 3)') 
    village = input() 

def checkVillage(chosenVillage): 
    print('You approch the city') 
    time.sleep(2) 
    print('It is filled with many stores,') 
    time.sleep(2) 
    print('In one store, a man is standing at it...') 
    time.sleep(2) 
    print('He has a gun, and has his hand by it') 
    time.sleep(2) 
    print('He says Welcome to my store,') 
    print() 
    time.sleep(2) 

    friendlyVillage = random.randint(1, 2, 3) 

    if chosenVillage == str(friendlyVillage): 
    print('And he sells you some weapons.') 
    else: 
    print('He looks at you and says:') 
    time.sleep(2) 
    print('You are not from around here,') 
    time.sleep(4) 
    print('And he shoots you! Better luck next time') 
    quit() 


playAgain = 'yes' 
while playAgain == 'yes' or playAgain == 'y': 

    displayIntro() 

    caveNumber = chooseCave() 

    checkCave(caveNumber) 

    print('Do you want to play again? (yes or no)') 
    playAgain = input() 

链接到此程序。

Answer 1

函数chooseVillage没有在任何点执行。如果您播放它，然后说no再次播放，您可以从命令行直接执行chooseVillage()运行代码。我猜你想要做的修改是，在caveNumber = chooseCave()之前，加入print('Do you want to play cave or village?')，然后使用输入有要么运行chooseCave()或chooseVillage()

如果您完成chooseVillage()代码搜索，你会看到它是唯一实例化什么一次，这是功能是def chooseVillage():，而不是随后执行。