Oracle 11g中的模式增长

Question

在Oracle中获得模式增长的最佳方式是什么？我尝试过使用许多dba_hist_表，并且它们中的任何一个似乎都无法让我在特定时间（7天）期间获得模式的大小和增长。这些表似乎保存表空间增长信息，而不是架构级别。

有人可以帮忙吗？

尝试下面的表格，

dba_hist_tablespace_stat，dba_hist_seg_stat，dba_hist_seg_stat_obj，DBA_HIST_SNAPSHOT等

Answer 1

入住此查询：

SELECT b.tsname tablspc_name , 
    MAX(b.used_size_mb) cur_used_size_mb , 
    ROUND(AVG(inc_used_size_mb),2) avg_incr_mb 
FROM 
    (SELECT a.days, 
    a.tsname , 
    used_size_mb , 
    used_size_mb - LAG (used_size_mb,1) OVER (PARTITION BY a.tsname ORDER BY a.tsname,a.days) inc_used_size_mb 
    FROM 
    (SELECT TO_CHAR(sp.begin_interval_time,'MM-DD-YYYY') days , 
     ts.tsname , 
     MAX(ROUND((tsu.tablespace_usedsize* dt.block_size)/(1024*1024),2)) used_size_mb 
    FROM dba_hist_tbspc_space_usage tsu , 
     dba_hist_tablespace_stat ts , 
     dba_hist_snapshot sp, 
     dba_tablespaces dt 
    WHERE tsu.tablespace_id = ts.ts# 
    AND tsu.snap_id   = sp.snap_id 
    AND ts.tsname    = dt.tablespace_name 
    AND sp.begin_interval_time > sysdate-7 
    GROUP BY TO_CHAR(sp.begin_interval_time,'MM-DD-YYYY'), 
     ts.tsname 
    ORDER BY ts.tsname, 
     days 
    ) a 
) b 
GROUP BY b.tsname 
ORDER BY b.tsname; 

和组由业主：

SELECT ds.owner as owner, 
    MAX(b.used_size_mb) cur_used_size_mb , 
    ROUND(AVG(inc_used_size_mb),2) avg_incr_mb 
FROM 
    (SELECT a.days, 
    a.tsname , 
    used_size_mb , 
    used_size_mb - LAG (used_size_mb,1) OVER (PARTITION BY a.tsname ORDER BY a.tsname,a.days) inc_used_size_mb 
    FROM 
    (SELECT TO_CHAR(sp.begin_interval_time,'MM-DD-YYYY') days , 
     ts.tsname , 
     MAX(ROUND((tsu.tablespace_usedsize* dt.block_size)/(1024*1024),2)) used_size_mb 
    FROM dba_hist_tbspc_space_usage tsu , 
     dba_hist_tablespace_stat ts , 
     dba_hist_snapshot sp, 
     dba_tablespaces dt 
    WHERE tsu.tablespace_id = ts.ts# 
    AND tsu.snap_id   = sp.snap_id 
    AND ts.tsname    = dt.tablespace_name 
    AND sp.begin_interval_time > sysdate-7 
    GROUP BY TO_CHAR(sp.begin_interval_time,'MM-DD-YYYY'), 
     ts.tsname 
    ORDER BY ts.tsname, 
     days 
    ) a 
) b 
JOIN dba_segments ds on ds.tablespace_name = b.tsname 
GROUP BY ds.owner 
ORDER BY ds.owner;