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以下是一个代码示例,它将文件名列表并将它们压缩到单个压缩文件中。我遇到的问题是,我希望filname所描述的文件位于zip压缩包的顶层(即当打开压缩包时,“clientName .... xml”是您首先看到的,而不是文件夹“XML”)。FSharp中的zip压缩文件的控制文件结构
let filename = sprintf "C:\\XML\\ClientName_%s.xml" (System.DateTime.Now.ToString("ddMMyyyy"))
use fs = new FileStream(filename, FileMode.Create)
let xmlSerializer = XmlSerializer(typeof<log>)
xmlSerializer.Serialize(fs,logObj)
fs.Close()
use zipfile = new ZipFile()
let basePath = path.Replace("/", "\\")
for fileObj in files do
let relativeFilePath = basePath + (fileObj.Filename).Replace("/", "\\")
printfn "%s" relativeFilePath
zipfile.AddFile(relativeFilePath) |> ignore
()
zipfile.AddFile(filename) |> ignore
let zipFileName = sprintf "C:\\XML\\Compliance_%s.zip" (System.DateTime.Now.ToString("ddMMyyyy"))
zipfile.Save(zipFileName)
完美,谢谢! – Ramy 2011-02-03 02:02:18