获取从列表视图中选择的联系人的详细信息

我正在设计应用程序，我希望允许用户选择多个联系人来发送消息。我已经使用以下代码成功检索了列表视图中带有复选框的用户列表。现在我想的是，当用户点击“完成”按钮后，所有选定联系人的应该是手机号码在EDITTEXT格式< + 919898xxxxxx>，里克< + 919988xxxxxx>，也即所有检索到的像约翰包含仅包含10位数字的电话号码，例如“9898xxxxxx”应该存储在一个由逗号（9898xxxxxx，9988xxxxxx）自动分隔的字符串中。我如何完成这项要求。获取从列表视图中选择的联系人的详细信息

public class ContactsActivity extends ListActivity { protected static final String TAG = null; public String[] Contacts = {}; public int[] to = {}; public ListView myListView; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_contacts); final Button done_Button = (Button) findViewById(R.id.done_Button); final Button clear_Button =(Button) findViewById(R.id.clear_Button); Cursor mCursor = getContacts(); startManagingCursor(mCursor); ListAdapter adapter = new SimpleCursorAdapter(this, android.R.layout.simple_list_item_multiple_choice, mCursor, Contacts = new String[] {ContactsContract.Contacts.DISPLAY_NAME }, to = new int[] { android.R.id.text1 }); setListAdapter(adapter); myListView = getListView(); myListView.setItemsCanFocus(false); myListView.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE); clear_Button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { Toast.makeText(getApplicationContext(),"Selections Cleared", Toast.LENGTH_SHORT).show(); ClearSelections(); } }); /** When 'Done' Button Pushed: **/ done_Button.setOnClickListener(new View.OnClickListener() { public void onClick (View v){ Log.i(TAG,":Done Button Selected:"); SparseBooleanArray selectedPositions = myListView.getCheckedItemPositions(); Log.i(TAG,"Number of Checked Positions: " + selectedPositions.size()); for (int i=0; i<selectedPositions.size(); i++) { if (selectedPositions.get(selectedPositions.keyAt(i)) == true) { //do stuff } } } }); } private void ClearSelections() { int count = this.myListView.getAdapter().getCount(); for (int i = 0; i < count; i++) { this.myListView.setItemChecked(i, false); } } private Cursor getContacts() { // Run query Uri uri = ContactsContract.Contacts.CONTENT_URI; String[] projection = new String[] { ContactsContract.Contacts._ID, ContactsContract.Contacts.DISPLAY_NAME}; String selection = ContactsContract.Contacts.HAS_PHONE_NUMBER + " = '" + ("1") + "'"; String[] selectionArgs = null; String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC"; return managedQuery(uri, projection, selection, selectionArgs, sortOrder); } @Override public boolean onCreateOptionsMenu(Menu menu) { getMenuInflater().inflate(R.menu.activity_contacts, menu); return true; } }

来源

2012-09-09 Tapan Desai

配置它你也许应该找出你从selectedPosition得到什么样的内容，让你.....代码的一部分。 – JoxTraex

@JoxTraex我没有得到所选联系人的真实电话号码，而是得到一些奇怪的值。 –

找出那些奇怪的值是什么，它应该与您的联系人数据相关。 – JoxTraex

终于

 done_Button.setOnClickListener(new View.OnClickListener() { 
     public void onClick (View v){ 
      String name = null; 
      String number = null; 
      long [] ids = myListView.getCheckedItemIds(); 
      for(long id : ids) { 
       Cursor contact = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, 
         ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[] { id + "" }, null); 
       while(contact.moveToNext()){ 
        name = contact.getString(contact.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)); 
        //name+=name; 
        number = contact.getString(contact.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
        //number+=number; 
       } 
       Toast.makeText(getApplicationContext(), "Name: " +name + "\n" + "Number: " + number , Toast.LENGTH_LONG).show(); 
      } 
     } 
    });

来源

2012-09-22 05:01:00

String numberListString = ""; 

for (int i=0; i<selectedPositions.size(); i++) { 
       if (selectedPositions.get(selectedPositions.keyAt(i)) == true) { 
        //do stuff 
        numberListString = numberListString + "," + numberAtCurrentSelectedPostion; 

       } 
      } 

mEditText.setText(numberListString);

来源

2012-09-09 13:32:29 Swayam

这不是特别有用。小心解释你如何获得'numberListString'？ – Luksprog

@Luksprog：抱歉，不清楚。 'numberListString'最初只是空的，我们会继续追加当前的数字。 – Swayam

试试这个在您完成按钮按： -

done_Button.setOnClickListener(new View.OnClickListener() { 
     public void onClick(View v) { 
      name.clear(); 
      number.clear(); 
      Log.i(TAG, ":Done Button Selected:"); 
      SparseBooleanArray selectedPositions = myListView 
        .getCheckedItemPositions(); 
      Log.i(TAG, 
        "Number of Checked Positions: " 
          + selectedPositions.size()); 
      Cursor cur = getContacts(); 
      for (int i = 0; i < selectedPositions.size(); i++) { 
       if (selectedPositions.get(selectedPositions.keyAt(i)) == true) { 
        // do stuff 
        cur.moveToPosition(selectedPositions.keyAt(i)); 
        name.add(cur.getString(1)); 
       } 
      } 
      for (int i = 0; i < name.size(); i++) { 
       Cursor lCursor = getContentResolver().query(
         ContactsContract.CommonDataKinds.Phone.CONTENT_URI, 
         null, "DISPLAY_NAME = ? ", 
         new String[] { name.get(i) }, null); 
       lCursor.moveToFirst(); 
       number.add(lCursor.getString(lCursor 
         .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))); 
       lCursor.close(); 
      } 

     } 
    });

其中名称和编号是String类型的数组列表。你会得到所有选定的名称和数字。现在，您可以按照自己的喜好在“编辑文本”中显示它

我想这会帮助你。

来源

2012-09-21 09:59:52

获取从列表视图中选择的联系人的详细信息

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