我有一个样本输入表作为ROW_NUMBER模拟在SQL Server 2000
Declare @input TABLE(Name VARCHAR(8))
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Joseph')
INSERT INTO @input(Name) values('Vicky')
INSERT INTO @input(Name) values('Jaesmin')
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Jaesmin')
INSERT INTO @input(Name) values('Vicky')
INSERT INTO @input(Name) values('Padukon')
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Jaesmin')
INSERT INTO @input(Name) values('Vick')
INSERT INTO @input(Name) values('Padukon')
INSERT INTO @input(Name) values('Joseph')
INSERT INTO @input(Name) values('Marya')
INSERT INTO @input(Name) values('Vicky')
另外我有一个符合表作为下
declare @t table(n int)
insert into @t select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all select 8 union all
select 9 union all select 10 union all select 11 union all
select 12 union all select 13 union all select 14 union all
select 15 union all select 16 union all select 17 union all
select 18 union all select 19 union all select 20
在SQL Server 2005中,如果我做的
Select rn, name from (
select ROW_NUMBER()over (order by Name) as rn , * from @input) x
where rn % 2 <> 0
我得到的输出为
rn name
1 Aryan
3 Aryan
5 Jaesmin
7 Jaesmin
9 Joseph
11 Padukon
13 Vick
15 Vicky
Bu我只限于Sql server 2000.我怎样才能得到相同的输出?
我试图与
SELECT name, (SELECT COUNT(*) FROM @input AS i2 WHERE i2.Name <= i1.Name) As rn
FROM @input AS i1
但输出是错误的
name rn
Aryan 4
Aryan 4
Joseph 9
Vicky 16
Jaesmin 7
Aryan 4
Jaesmin 7
Vicky 16
Padukon 12
Aryan 4
Jaesmin 7
Vick 13
Padukon 12
Joseph 9
Marya 10
Vicky 16
@marc_s:作为写@Maximilian Mayerl - 它是更多钞票)。 – TcKs
理货桌有什么意义? – gbn
根据@Maximilians的回答,您需要向'@ Input'添加一列或将数据插入到另一个临时表/表变量中,因为SQL Server无法订购例如名字='Aryan'的四行 –