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我试图运行基于JPA的示例项目。我始终得到标题中的错误。没有EntityManager的持久性提供者命名（休眠）
我看这里： No Persistence provider for EntityManager named
但没有发现有效的解决方案出现。
这里是我的pom.xml：
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>~path.example</groupId>
<artifactId>example</artifactId>
<version>1.0-SNAPSHOT</version>
<dependencies>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>5.1.6</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>ejb3-persistence</artifactId>
<version>3.3.2.Beta1</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>4.3.9.Final</version>
</dependency>
<dependency>
<groupId>org.eclipse.jst.server.generic</groupId>
<artifactId>oc4j</artifactId>
<version>1.5.105-v200709061325</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>4.0.1.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-validator</artifactId>
<version>4.2.0.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate.common</groupId>
<artifactId>hibernate-commons-annotations</artifactId>
<version>4.0.1.Final</version>
<classifier>tests</classifier>
</dependency>
<dependency>
<groupId>org.hibernate.javax.persistence</groupId>
<artifactId>hibernate-jpa-2.0-api</artifactId>
<version>1.0.1.Final</version>
</dependency>
<dependency>
<groupId>javax.validation</groupId>
<artifactId>validation-api</artifactId>
<version>1.0.0.GA</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.slf4j</groupId>
<artifactId>slf4j-api</artifactId>
<version>1.6.4</version>
</dependency>
<dependency>
<groupId>org.jboss.logging</groupId>
<artifactId>jboss-logging</artifactId>
<version>3.1.0.CR2</version>
</dependency>
<dependency>
<groupId>org.slf4j</groupId>
<artifactId>slf4j-log4j12</artifactId>
<version>1.6.4</version>
</dependency>
<dependency>
<groupId>org.jboss.spec</groupId>
<artifactId>jboss-javaee-6.0</artifactId>
<version>1.0.0.Final</version>
<type>provided</type>
<scope>pom</scope>
</dependency>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.11</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.jboss.arquillian.junit</groupId>
<artifactId>arquillian-junit-container</artifactId>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.jboss.spec</groupId>
<artifactId>jboss-javaee-6.0</artifactId>
<version>1.0.0.Final</version>
<type>pom</type>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.jboss.arquillian.container</groupId>
<artifactId>arquillian-weld-ee-embedded-1.1</artifactId>
<version>1.0.0.CR3</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.jboss.weld</groupId>
<artifactId>weld-core</artifactId>
<version>1.1.5.Final</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.slf4j</groupId>
<artifactId>slf4j-simple</artifactId>
<version>1.6.4</version>
<scope>test</scope>
</dependency>
</dependencies>
<dependencyManagement>
<dependencies>
<dependency>
<groupId>org.jboss.arquillian</groupId>
<artifactId>arquillian-bom</artifactId>
<version>1.1.8.Final</version>
<scope>import</scope>
<type>pom</type>
</dependency>
</dependencies>
</dependencyManagement>
</project>
这可能是我有一些依赖，我不需要。由于我没有经验，我必须诚实地承认，我非常绝望并且寻找任何可能的答案，并且在那个过程中我添加了一些根本不可用的依赖关系。
这是应该做的EntityManager
package ~path.examples.service;
import ~path.examples.testjpa.domain.Person;
import javax.persistence.*;
/**
* Created by ME on 2015-04-22.
*/
public class JpaTest {
public static void main(String args[]) {
EntityManagerFactory entityManagerFactory = Persistence.createEntityManagerFactory("jpaTest");
EntityManager em = entityManagerFactory.createEntityManager();
EntityTransaction userTransaction = em.getTransaction();
userTransaction.begin();
Person person = new Person();
person.setFirstName("Charles");
person.setSurname("Dickens");
em.persist(person);
userTransaction.commit();
em.close();
entityManagerFactory.close();
}
}
而且类：
Im相当肯定，所有的文件都在合适的位置，我也有一些问题，我，但我似乎已经消除了这个问题（其他错误比以前弹出:) :)
这可能是显而易见的，我错过了，在此先感谢f或任何帮助！
编辑：这很可能是问题在于persistance.xml文件，所以在这里（谢谢指出它）。该文件的位置为src /主/资源/ META-INF
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="JpaTest" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>~path.examples.testjpa.domain.Person</class>
<properties>
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.format_sql" value="true" />
<property name="hibernate.dialect" value="org.hibernate.dialect.DerbyDialect" />
<property name="hibernate.hbm2ddl.auto" value="update" />
</properties>
</persistence-unit>
</persistence>
你有一个persistence.xml文件吗？ – Vyncent
并假设是：在哪里？ “我很确定”不是隐藏细节的理由，因为您犯了一个错误的选项仍然非常多。你自己这么说。 – Gimby
是的，当然我有，我打算发布它。编辑，谢谢指出，只是忘了:) 顺便说一下，位置是正确的几乎肯定（我必须承认我试验了一点，在任何其他地方它甚至不会被检测到），但它很可能是文件内有一个错误，我没有看到。 –