CKEditor从选择中删除选项

Question

我想从CKEditor的'链接'选项卡上的linkType选择元素中删除两个选项。

我该怎么做？它在文档中说使用remove函数，但我不明白如何将它指向正确的元素。

http://docs.ckeditor.com/#!/api/CKEDITOR.ui.dialog.select

Answer 1

我们正在使用这种从对话框中删除linkType和其他多余的东西：

CKEDITOR.on('dialogDefinition', function(ev) { 
    var dialogName = ev.data.name; 
    var dialogDefinition = ev.data.definition; 
    if (dialogName == 'link') { 
     //REMOVE NOT REQUIRED TABS 
     dialogDefinition.removeContents('upload'); 
     dialogDefinition.removeContents('advanced'); 

     var infoTab = dialogDefinition.getContents('info'); 
     //REMOVE COMBO 
     infoTab.remove('linkType'); 
    } 
}); 

编辑： - 作为this page和this answer描述，你可以得到元素，并为它指定的选项。

var infoTab = dialogDefinition.getContents('info'); 
//REMOVE COMBO 
var lt=infoTab.get('linkType'); 
lt['items']=[['URL','Link to URL']]; 

Answer 2

我只是找到了答案在这里：http://ckeditor.com/forums/Support/Remove-options-link-drop-down

CKEDITOR.on('dialogDefinition', function(ev) { 
    // Take the dialog name and its definition from the event 
    // data. 
    var dialogName = ev.data.name; 
    var dialogDefinition = ev.data.definition; 

    // Check if the definition is from the dialog we're 
    // interested on (the "Link" dialog). 
    if (dialogName == 'link') { 
     // Get a reference to the "Link Info" tab. 
     var infoTab = dialogDefinition.getContents('info'); 

     // Get a reference to the link type 
     var linkOptions = infoTab.get('linkType'); 

     // set the array to your preference 
     linkOptions['items'] = [['URL', 'url'], ['Link to anchor in the text', 'anchor']]; 
    } 
});