我是PHP和Javascript的新手,刚开始有两种形式的网站,一种形式有5个复选框,另一种形式有5个单选按钮。当您更改单选按钮的单选按钮时,它会刷新页面并使用新值。与复选框相同。不幸的是,如果您更改其中一个表单,然后更改其他表单,则第一个表单值将不再存在。double form refresh
下面的代码:
<form name='form2' method='post'>
<input type="radio" name="group1" value="all" onClick="if (this.checked) this.form.submit();" <?php if ($_REQUEST['group1'] == null || $_REQUEST['group1'] == "all"){ echo "checked='checked'";}?>/> All<br>
<input type="radio" name="group1" value="Example" onClick="if (this.checked) this.form.submit();" <?php if ($_REQUEST['group1'] == "Example"){ echo "checked='checked'";}?>/> Example<br>
<input type="radio" name="group1" value="clifton" onClick="if (this.checked) this.form.submit();" <?php if ($_REQUEST['group1'] == "clifton"){ echo "checked='checked'";}?>/> Clifton<br/>
<input type="radio" name="group1" value="fruita" onClick="if (this.checked) this.form.submit();" <?php if ($_REQUEST['group1'] == "fruita"){ echo "checked='checked'";}?>/> Fruita<br/>
<input type="radio" name="group1" value="loma" onClick="if (this.checked) this.form.submit();" <?php if ($_REQUEST['group1'] == "loma"){ echo "checked='checked'";}?>/> Loma<br/>
</form>
<form name='form3' method='post'>
<input type="checkbox" name="option1" value="smoking" onClick="if (this.checked) this.form.submit();" <?php if(isset($_REQUEST['option1'])){ echo "checked='checked'";} ?>/> No Smoking<br>
<input type="checkbox" name="option2" value="kids" onClick="if (this.checked) this.form.submit();" <?php if(isset($_REQUEST['option2'])){ echo "checked='checked'";} ?>/>Good for Kids<br>
<input type="checkbox" name="option3" value="wheelchair" onClick="if (this.checked) this.form.submit();" <?php if(isset($_REQUEST['option3'])){ echo "checked='checked'";} ?>/>Wheelchair Accessible<br>
<input type="checkbox" name="option4" value="alcohol" onClick="if (this.checked) this.form.submit();" <?php if(isset($_REQUEST['option4'])){ echo "checked='checked'";} ?>/>Serves Alcohol<br>
<input type="checkbox" name="option5" value="delivery" onClick="if (this.checked) this.form.submit();" <?php if(isset($_REQUEST['option5'])){ echo "checked='checked'";} ?>/>Delivery Servicee<br>
</form>
我试图让这两种形式输入要保存的其他形式的变化也是如此。 任何帮助将高度赞赏。谢谢!
你已经描述了一个问题,但问题在哪里? – bos 2012-07-20 00:53:20
不能为他们说话,但我认为OP希望两套输入都能保持其价值。 – machineghost 2012-07-20 00:54:18
哎呀对不起@machineghost是正确的...我会更新 – infinity 2012-07-20 00:55:07