Django在课堂上的订购代码

Question

我需要一个更好的解决方案，以尝试在下面达成目标。我有一个形式，这种形式需要决定了代码以下项目的顺序...

class ContactCSVModel(CsvModel): 
    first_name = CharField() 
    last_name = CharField() 
    company = CharField() 
    mobile = CharField() 
    group = DjangoModelField(Group) 
    contact_owner = DjangoModelField(User) 

例如...

class ContactCSVModel(CsvModel): 
    if form.col1.value == "first_name": 
     first_name = CharField() 
    elif form.col1.value == "last_name": 
     last_name = CharField() 

也许

class ContactCSVModel(CsvModel): 
     [column.col1.value] = CharField() 
     [column.col2.value] = CharField() 

但这不会工作，因为它会尝试分配值不mak e it first_name = CharField（）等

正如你所看到的，我最终再次为col2，col3等做了这样的事情，并以'if语句'的'lot'结束。

有没有更好的方法，例如？

谢谢。

Forms.py

COL_CHOICES = [ 
    ('NONE', 'No Import'), 
    ('first_name', 'First Name'), 
    ('last_name', 'Last Name'), 
    ('company', 'Company'), 
    ('mobile', 'Mobile Number'), 
    ('email', 'Email Address'), 
    ] 


class ConfiguratorForm(forms.Form): 
    col1 = forms.TypedChoiceField(choices=COL_CHOICES, initial='first_name') 
    col2 = forms.TypedChoiceField(choices=COL_CHOICES, initial='first_name') 
    col3 = forms.TypedChoiceField(choices=COL_CHOICES, initial='first_name') 
    col4 = forms.TypedChoiceField(choices=COL_CHOICES, initial='first_name') 
    col5 = forms.TypedChoiceField(choices=COL_CHOICES, initial='first_name') 

这是我不变类，因为它现在是：

def import_data(column, *args, **kw): 
    # make custom ContactCSVModel 
    class ContactCSVModel(CsvModel): 
     # IF column == x 



     first_name = CharField() 
     mobile = CharField() 
     last_name = CharField() 
     company = CharField() 
     group = DjangoModelField(Group) 
     contact_owner = DjangoModelField(User) 

     class Meta: 
      delimiter = "," 
      dbModel = Contact 
      update = {'keys': ["mobile", "group"]} 

    return ContactCSVModel.import_data(*args, **kw) 

Answer 1

你可以添加字段到模型之后，如：

class ContactCSVModel(CsvModel): 
    pass 

for form_field in form: 
    field_name = form_field.value 
    model_field = CharField() 
    model_field.contribute_to_class(ContactCSVModel, field_name) 

例如（使用Django 1.5）：

from django.db import models 

class ContactCSVModel(models.Model): 
    pass 

for field_name in ('first_name', 'mobile', 'last_name'): 
    model_field = models.CharField() 
    model_field.contribute_to_class(ContactCSVModel, field_name) 

print [f.name for f in ContactCSVModel._meta.fields] 

# prints: 
[u'id', 'first_name', 'mobile', 'last_name']