的Python列表

Question

我目前正试图排序的表格清单列表排序的字母数字：

[["Chr1", "949699", "949700"],["Chr11", "3219", "444949"], 
["Chr10", "699", "800"],["Chr2", "232342", "235345234"], 
["ChrX", "4567", "45634"],["Chr1", "950000", "960000"]] 

使用内置sorted()，我得到：

[“CHR1”， ''949699'，'949700']，['Chr1'，'950000'，'960000']，['Chr10'，'699'，'800']，['Chr11'，'3219'，'444949'] ，''Chr2'，'232342'，'235345234']，['ChrX'，'4567'，'45634']]

但我希望“Chr2”在“Chr10”之前。我目前的解决方案包括改编自页一些代码：Does Python have a built in function for string natural sort?

我目前的解决办法是这样的：

import re 

def naturalSort(l): 
    convert= lambda text: int(text) if text.isdigit() else text.lower() 
    alphanum_key= lambda key: [convert(c) for c in re.split('([0-9]+)', key)] 
    if isinstance(l[0], list): 
     return sorted(l, key= lambda k: [alphanum_key(x) for x in k]) 
    else: 
     return sorted(l, key= alphanum_key) 

屈服正确的顺序：

[['Chr1', '949699', '949700'], ['Chr1', '950000', '960000'], ['Chr2', '232342', '235345234'], ['Chr10', '699', '800'], ['Chr11', '3219', '444949'], ['ChrX', '4567', '45634']] 

有没有更好的方式来做到这一点？

Answer 1

它是否喜欢：

In [1]: l = [["Chr1", "949699", "949700"],["Chr11", "3219", "444949"],["Chr10", "699", "800"],["Chr2", "232342", "235345234"],["ChrX", "4567", "45634"],["Chr1", "950000", "960000"]] 

In [2]: sorted(l, key=lambda x: int(x[0].replace('Chr', '')) if x[0].replace('Chr', '').isdigit() else x[0]) 
Out[2]: 
[['Chr1', '949699', '949700'], 
['Chr1', '950000', '960000'], 
['Chr2', '232342', '235345234'], 
['Chr10', '699', '800'], 
['Chr11', '3219', '444949'], 
['ChrX', '4567', '45634']] 

或者更优雅的变体：

sorted(l, key=lambda x: int(''.join([i for i in x[0] if i.isdigit()])) if re.findall(r'\d+$', x[0]) else x[0]) 

Answer 2

这里有一个更紧凑的解决方案：

natkey = lambda e: [x or int(y) for x, y in re.findall(r'(\D+)|(\d+)', e)] 
print sorted(data, key=lambda item: map(natkey, item))