我有一对多模型。 有很多练习的锻炼细节。获取对象的属性
我能够显示练习的所有数据,但我只需要属性'标题'。
在控制器I有
public function getDetails($id){
$details = WorkoutDetails::where('parent_id','=',$id)->get();
return View::make('menu_renderer.partials.details')->with('details', $details);
}
而在HTML我有
@foreach($details as $detail)
<div>
<ul>
{{$detail->exercises}}
</ul>
</div>
@endforeach
并且输出是:
[{ “ID”:1, “TYPE_ID”: 0,“title”:“Exercise one”,“details”:“Details exercise one”,“media”:“5”,“created_at”:“ - 0001-11-30 00:00:00”,“的updated_at “:” - 0001 -11-30 00:00:00“}] [{”id“:2,”type_id“:0,”标题“:”练习二“,”细节“:”细节 练习二“,”媒体“ :“2”,“created_at”:“ - 0001-11-30 00:00:00”,“updated_at”:“ - 0001-11-30 00:00:00”}] [{“id”: 3,“type_id”:0,“标题”:“练习三”,“细节”:“细节 练习三”,“媒体”:“6”,“created_at”:“ - 0001-11-30 00: 00:00“,”updated_at“:” - 0001-11-30 00:00:00“}] [{”id“:4,”type_id“:0,”title“:”Exercise four“,”details “:”详细信息 练习四“,”媒体“:”6“,”created_at“:” - 0001-11-30 00:00:00“,”updated_at“:” - 0001-11-30 00:00 :00“}]
哪个不错,但我只需要标题或细节。
我试图
@foreach($details as $detail)
<div>
<ul>
{{$detail->exercises->title}}
</ul>
</div>
@endforeach
或
@foreach($details as $detail)
<div>
<ul>
{{$detail->exercises.title}}
</ul>
</div>
@endforeach
或
@foreach($details as $detail)
<div>
<ul>
{{$detail->exercises[title]}}
</ul>
</div>
@endforeach
但没有......
谁能给我一个提示,我怎么能只显示了标题或每个Ex的细节ercise属于WorkoutDetails模型?
谢谢!
它工作!非常感谢你 !! – codi05ro