移调列值成排SQL

我有一个展示的项目负责人（RES_）如下表：移调列值成排SQL

ID NUMBER BK no_ Res 
LUC00003  BK001  CLARETH 
LUC00003  BK001  MARC 
LUC00009  BK001  CLARETH 
LUC00009 BK001  MICHAEL

我想在一行中显示RES_而不是列，为了得到每一行对应一个ID，如下图所示：

ID NUMBER BK no_ Res 1  Res2 
LUC00003  BK001  CLARETH MARC 
LUC00009  BK001  CLARETH MICHAEL

这里下面的查询：

SELECT 
    C.[ID NUMBER], 
    CA.[BK No_], 
    B.[Res] 
FROM [IDList] C 
LEFT JOIN [BK list] CA ON C.[ID NUMBER] = CA.[ID NUMBER] 
LEFT JOIN [Res List] B ON B.[ID NUMBER]= C.[ID NUMBER] AND B.[BK No_]=CA.[BK No_]

来源

2017-04-27 Nic

，如果你想这个解决方案，为任意数量的RES_价值的工作，你不能动态地添加colums。如果您知道Res_将会有一个或两个值，则可以创建两列，如果未找到任何结果，那么可能为空。然而，你可以将所有结果连接成一个coluimn，例如：http://stackoverflow.com/questions/194852/concatenate-many-rows-into-a-single-text-string – mortb

你需要“Res 1”和“Res 2”作为附加值PER行，之后您可以使用[PIVOT]（https://docs.microsoft.com/en-us/sql/t-sql/queries/from-using-pivot-and-unpivot） - 函数 – swe

也许这个问题可以帮助你，它的一个可能的重复：http://stackoverflow.com/questions/41768834/sql-pivot-with-multiple-values – swe

使用条件aggregatio N：

select 
    id_number 
    , bk_no 
    , Res1 = max(case when rn = 1 then Res end) 
    , Res2 = max(case when rn = 2 then Res end) 
from (
    select * 
    , rn = row_number() over (partition by id_number, bk_no order by res) 
    from t 
) sub 
group by id_number, bk_no

rextester演示：http://rextester.com/DFCC86645

回报：

+-----------+-------+---------+---------+ 
| id_number | bk_no | Res1 | Res2 | 
+-----------+-------+---------+---------+ 
| LUC00003 | BK001 | CLARETH | MARC | 
| LUC00009 | BK001 | CLARETH | MICHAEL | 
+-----------+-------+---------+---------+

动态pivot()版本：

declare @cols nvarchar(max); 
declare @sql nvarchar(max); 

    select @cols = stuff((
    select distinct 
     ',' + quotename('Res' 
      +convert(varchar(10),row_number() over (
       partition by id_number, bk_no 
       order by  res 
     )) 
     ) 
     from t 
     for xml path (''), type).value('.','nvarchar(max)') 
    ,1,1,''); 

select @sql = ' 
select id_number, bk_no, ' + @cols + ' 
    from (
    select 
     id_number 
     , bk_no 
     , Res 
     , rn=''Res'' + convert(varchar(10),row_number() over (
       partition by id_number, bk_no 
       order by  res 
     )) 
     from t 
    ) as a 
pivot (max([Res]) for [rn] in (' + @cols + ')) p'; 
select @sql as CodeGenerated; 
exec sp_executesql @sql;

回报：

+-----------------------------------------------------------------+ 
|       CodeGenerated       | 
+-----------------------------------------------------------------+ 
|  select id_number, bk_no, [Res1],[Res2]      | 
|  from (             | 
|   select             | 
|    id_number           | 
|   , bk_no            | 
|   , Res             | 
|   , rn='Res' + convert(varchar(10),row_number() over (| 
|     partition by id_number, bk_no     | 
|     order by  res        | 
|    ))            | 
|   from t            | 
|   ) as a            | 
|  pivot (max([Res]) for [rn] in ([Res1],[Res2])) p   | 
+-----------------------------------------------------------------+

+-----------+-------+---------+---------+ 
| id_number | bk_no | Res1 | Res2 | 
+-----------+-------+---------+---------+ 
| LUC00003 | BK001 | CLARETH | MARC | 
| LUC00009 | BK001 | CLARETH | MICHAEL | 
+-----------+-------+---------+---------+

来源

2017-04-27 12:17:31 SqlZim

移调列值成排SQL

回答

相关问题