2013-04-23 19 views
1

我在我的服务器上安装了Appdynamics lite,当我用root用户运行我的tomcat实例时,它工作正常。但是从创建新用户“Tomcat”并开始执行我的apache tomcat与此用户,我无法运行appdynamics。我已将这个位置的javaagent复制到tomcat“/ home/tomcat/profiler/AppServerLite”的所有权限(读,写,执行)。安装appdynamics的问题

Install Directory resolved to[/home/tomcat/profiler/AppServerLite] 
java.lang.RuntimeException: Invalid Agent Installation Directory [/home/tomcat/profiler/AppServerLite] 
     at com.singularity.ee.agent.appagent.AgentEntryPoint.addThirdPartyURLs(AgentEntryPoint.java:190) 
     at com.singularity.ee.agent.appagent.AgentEntryPoint.premain(AgentEntryPoint.java:144) 
     at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
     at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) 
     at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 
     at java.lang.reflect.Method.invoke(Method.java:616) 
     at sun.instrument.InstrumentationImpl.loadClassAndStartAgent(InstrumentationImpl.java:343) 
     at sun.instrument.InstrumentationImpl.loadClassAndCallPremain(InstrumentationImpl.java:358) 
Install Directory resolved to[/home/tomcat/profiler/AppServerLite] 
java.lang.RuntimeException: Invalid Agent Installation Directory [/home/tomcat/profiler/AppServerLite] 
     at com.singularity.ee.agent.appagent.AgentEntryPoint.addThirdPartyURLs(AgentEntryPoint.java:190) 
     at com.singularity.ee.agent.appagent.AgentEntryPoint.premain(AgentEntryPoint.java:144) 
     at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
     at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) 
     at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 
     at java.lang.reflect.Method.invoke(Method.java:616) 
     at sun.instrument.InstrumentationImpl.loadClassAndStartAgent(InstrumentationImpl.java:343) 
     at sun.instrument.InstrumentationImpl.loadClassAndCallPremain(InstrumentationImpl.java:358) 
18 Apr, 2013 1:57:03 PM org.apache.catalina.core.AprLifecycleListener init 

回答