Spring Security with vaadin maven project中的数据库

Question

我有一个vaadin maven项目，我在spring security中集成，所以我能够看到spring security的默认登录形式。 现在我想从postgres数据库获得用户请帮助我吗？你有任何tuto或书吗？感谢“SA很多

Answer 1

作为例子（尊重罗兰Krügers例子）春季启动应用+ SpringSecurity + Vaadin4Spring＃Hibernate，就必须在application.properties定义以下属性：

# DATASOURCE 
spring.datasource.url=jdbc:postgresql://localhost/myDB 
spring.datasource.username=myuser 
spring.datasource.password=mypwd 
spring.datasource.driverClassName=org.postgresql.Driver 
spring.datasource.xa.data-source-class-name=org.postgresql.xa.PGXADataSource 
spring.datasource.pinGlobalTxToPhysicalConnection="true" 

# one transaction manager via view 
spring.jpa.open-in-view=true 
# for mapping models and attributes to table names and column names 
spring.jpa.hibernate.naming_strategy=org.hibernate.cfg.EJB3NamingStrategy 
spring.jta.default-transaction-timeout=2000 

使用application.properties在您的应用程序下面的注释添加到您的主类：

@PropertySources({ 
    @PropertySource({"classpath:application.properties"}) 
}) 

现在，用户的实体可以是这样的：

import javax.persistence.Column; 
import javax.persistence.Entity; 
import javax.persistence.Id; 
import javax.persistence.GeneratedValue; 
import javax.persistence.GenerationType; 

@Entity 
@Table(name = "USER") 
public class User { 

    @Id 
    @GeneratedValue(strategy = GenerationType.IDENTITY) 
    @Column(name = "ID", nullable = false, updatable = false) 
    private Long id; 

    @Column(name = "LAST_NAME", nullable = false) 
    private String lastName; 

    @Column(name = "FIRST_NAME", nullable = false) 
    private String firstName; 

    @Column(name = "LOGGED_IN") 
    private boolean loggedIn; 

    public Long getId() { 
     return id; 
    } 

    public void setId(Long id) { 
     this.id = id; 
    } 

    public String getLastName() { 
     return lastName; 
    } 

    public void setLastName(String lastName) { 
     this.lastName = lastName; 
    } 

    public String getFirstName() { 
     return firstName; 
    } 

    public void setFirstName(String firstName) { 
     this.firstName = firstName; 
    } 

    public boolean isLoggedIn() { 
     return loggedIn; 
    } 

    public void setLoggedIn(boolean loggedIn) { 
     this.loggedIn = loggedIn; 
    } 
} 

之后，你必须定义对Hibernate的存储库接口：

/** 
*Spring auto repository for database access of User objects. 
**/ 
public interface UserRepository extends JpaRepository<User, Long> { 

    Optional<User> findOneByName(String userName); 
} 

现在你可以做这样的事情在你的登录方法：

... 
vaadinSecurity.login(userName.getValue(), passwordField.getValue()); 
Optional<User> ouser = userRepository.findOneByName(userName); 
if (ouser.isPresent()) { 
    User user = ouser.get(); 
    user.setLoggedIn(true); 
} 
...