正如标题所述,我创建了D3线/面积图,我发现很难让图的宽度保持不变,这取决于我给出的数据量它渲染时,它会相应地缩放图形的宽度,但我不确定如何让它保持恒定的宽度,而不管给定的数据量如何,这是我想实现的。D3线图没有填充整个svg宽度
我想它与x和y坐标的缩放有关,但我暂时陷入困境,似乎无法弄清楚它为什么这样做。
这里是我迄今为止代码,
//dimensions and margins
var width = 625,
height = 350,
margin = 5,
// get the svg and set it's width/height
svg = d3.select("#main")
.attr("width", width)
.attr("height", height);
//initialize the graph
init([
[12345,42345,32345,22345,72345,62345,32345,92345,52345,22345],
[1234,4234,3234,2234,7234,6234,3234,9234,5234,2234]
]);
$("button").live('click', function(){
var id = $(this).attr("id");
if(id == "one"){
updateGraph([
[52345,32345,12345,22345,62345,72345,92345,32345,22345,22345,52345,32345,12345,22345,62345,72345,92345,32345,22345,22345,52345,32345,12345,22345,62345,72345,92345,32345,22345,22345],
[4234,12345,2234,32345,6234,7234,9234,3234,2234,2234,4234,1234,2234,3234,6234,7234,9234,3234,2234,2234,4234,1234,2234,3234,6234,7234,9234,3234,2234,2234]
]);
}else if(id == "two"){
updateGraph([
[12345,42345,32345,22345,72345,62345,32345,92345,52345,22345,12345,42345,32345,22345,72345,62345,32345,92345,52345,22345,12345,42345,32345,22345,72345],
[1234,2345,3234,2234,7234,6234,3234,9234,5234,2234,1234,4234,3234,2234,7234,6234,3234,9234,5234,2234,1234,4234,3234,2234,7234]
]);
}
});
function init(data){
var x = d3.scale.linear()
.domain([0,data[0].length])
.range([margin, width-margin]),
y = d3.scale.linear()
.domain([0,d3.max(data[0])])
.range([height-margin, margin]),
/* line path generator */
line = d3.svg.line().interpolate('monotone')
.x(function(d,i) { return x(i); })
.y(function(d) { return y(d); }),
/* area path generator */
area = d3.svg.area().interpolate('monotone')
.x(line.x())
.y1(line.y())
.y0(y(0)),
groups = svg.selectAll("g")
.data(data)
.enter()
.append("g");
svg.select("g")
.selectAll("circle")
.data(data[0])
.enter()
.append("circle")
.attr("class", "dot")
.attr("cx", line.x())
.attr("cy", line.y())
.attr("r", 4);
/* add the areas */
groups.append("path")
.attr("class", "area")
.attr("d",area)
.style("fill", function(d,i) { return (i == 0 ? "steelblue" : "red"); });
/* add the lines */
groups.append("path")
.attr("class", "line")
.attr("d", line);
}
function updateGraph(data){
var x = d3.scale.linear()
.domain([0,data[0].length])
.range([margin, width-margin]),
y = d3.scale.linear()
.domain([0,d3.max(data[0])])
.range([height-margin, margin]),
/* line path generator */
line = d3.svg.line().interpolate('monotone')
.x(function(d,i) { return x(i); })
.y(function(d) { return y(d); }),
/* area path generator */
area = d3.svg.area().interpolate('monotone')
.x(line.x())
.y1(line.y())
.y0(y(0));
groups = svg.selectAll("g")
.data(data),
circles = svg.select("g")
.selectAll("circle");
circles.data(data[0])
.exit().remove();
circles.data(data[0])
.enter().append("circle")
.attr("class", "dot")
.attr("cx", line.x())
.attr("cy", line.y())
.attr("r", 4);
/* animate circles */
circles.data(data[0])
.transition()
.duration(1000)
.attr("cx", line.x())
.attr("cy", line.y());
/* animate the lines */
groups.select('.line')
.transition()
.duration(1000)
.attr("d",line);
/* animate the areas */
groups.select('.area')
.transition()
.duration(1000)
.attr("d",area);
}
除了作为一个小提琴http://jsfiddle.net/JL33M/
谢谢!
感谢您的详细解答! :)有一点让我困惑,虽然我指定了一个固定的宽度,但图表从来没有填满整个容器,我知道它会缩放,但是如果它不能将图形放大到宽度和高度,我会给它?我认为这是非常不一致的,尽管它是有道理的,但它在试图实现数据集之间的一致性时会产生一个真正的问题。所以,如果我正确地理解了你,我的代码应该会产生一个图形,以适应我指定它使用的整个宽度。 – Odyss3us
是不是因为你减去了保证金? –
如果只是它会“拉伸”域值,以某种理智的方式。结果根本没有模式。有时候,较大的值会得到一个瘦的结果,而较小的值会得到一个宽的结果有时候情况恰恰相反。应该发生什么,最长的条被设置为最大宽度,并且所有其他比例都按比例缩放。 – JosephK