如何执行MySQL UPSERT

这就是我的表的样子。如何执行MySQL UPSERT

CREATE TABLE `answers` (
`id` INT(11) NOT NULL AUTO_INCREMENT, 
`basicinfo_id` INT(11) NOT NULL, 
`question_id` INT(11) NOT NULL, 
`answer` INT(11) NOT NULL, 
PRIMARY KEY (`id`), 
INDEX `question_id` (`question_id`), 
INDEX `basicinfo_id` (`basicinfo_id`), 
CONSTRAINT `basicinfo_id` FOREIGN KEY (`basicinfo_id`) REFERENCES `basic_info` (`id`) ON UPDATE NO ACTION ON DELETE NO ACTION, 
CONSTRAINT `question_id` FOREIGN KEY (`question_id`) REFERENCES `questions` (`id`) ON UPDATE NO ACTION ON DELETE NO ACTION) COLLATE='latin1_swedish_ci' ENGINE=InnoDB AUTO_INCREMENT=3383;

这是数据如何能像

我想，如果他们已经存在“basicinfo_id”更新的答案。或如果我更改question_id 1，2和3的答案。我该如何插入数据。

我试过这个查询，但它没有更新结果。

INSERT INTO answers (basicinfo_id, question_id, answer) VALUES('98', 1, '1'),('98', 2, '1'),('98', 3, '1'),('98', 4, '1'),('98', 5, '1') ON DUPLICATE KEY UPDATE basicinfo_id = 98;

我已经定义了一个复合唯一键现在这是它的样子，但它仍然没有工作。

CREATE TABLE `answers` (
`id` INT(11) NOT NULL AUTO_INCREMENT, 
`basicinfo_id` INT(11) NOT NULL, 
`question_id` INT(11) NOT NULL, 
`answer` INT(11) NOT NULL, 
PRIMARY KEY (`id`), 
UNIQUE INDEX `basicinfo_id_question_id` (`basicinfo_id`, `question_id`), 
INDEX `question_id` (`question_id`), 
INDEX `basicinfo_id` (`basicinfo_id`), 
CONSTRAINT `basicinfo_id` FOREIGN KEY (`basicinfo_id`) REFERENCES `basic_info` (`id`) ON UPDATE NO ACTION ON DELETE NO ACTION, 
CONSTRAINT `question_id` FOREIGN KEY (`question_id`) REFERENCES `questions` (`id`) ON UPDATE NO ACTION ON DELETE NO ACTION) COLLATE='latin1_swedish_ci' ENGINE=InnoDB AUTO_INCREMENT=3718;

来源

2016-08-23 Shaonline

永远不会发生更新插入。你永远不会导致重复的密钥违规。只有当存在唯一的密钥违规时，“重复密钥”才会实际触发。没有重点违规，没有更新。 –

对不起，如果我来这里有点无知，但如果我设置basicinfo_id为UNIQUE它不会允许重复basicinfo_id，我不想但如果我设置basicinfo_id和question_id都作为复合独特的关键，那么它是可能的。我有什么意义吗？ – Shaonline

是的，在这种情况下，您需要一个复合唯一密钥。 –

你ON DUPLICATE KEY UPDATE basicinfo_id = 98;是畸形

试试这个： ON DUPLICATE KEY UPDATE 'answer' = VALUES('answer');

如果一个唯一的密钥已经存在，它会更新answer场

来源

2016-08-23 19:53:03 Sylwit

如何执行MySQL UPSERT

回答

相关问题