java和php在同一台机器上?
PHP到Java
http://php-java-bridge.sourceforge.net/pjb/
所以,我有一个非常基本的测试设置,看看我是否可以从一个PHP网页将数据发送到同一台服务器上运行的Java应用程序。
的Java应用程序是死的简单,它只是在其上侦听数据
import java.io.*;
import java.net.*;
class TCPServer
{
public static void main(String argv[]) throws Exception
{
String clientSentence;
String capitalizedSentence;
ServerSocket welcomeSocket = new ServerSocket(6789);
while(true)
{
Socket connectionSocket = welcomeSocket.accept();
BufferedReader inFromClient =
new BufferedReader(new InputStreamReader(connectionSocket.getInputStream()));
DataOutputStream outToClient = new DataOutputStream(connectionSocket.getOutputStream());
clientSentence = inFromClient.readLine();
System.out.println("Received: " + clientSentence);
capitalizedSentence = clientSentence.toUpperCase() + '\n';
outToClient.writeBytes(capitalizedSentence);
connectionSocket.close();
}
}
}
方法1
$host = "tcp://localhost";
$port = 6789;
$data = 'test' . PHP_EOL;
$errstr = '';
$errno = '';
if (($fp = fsockopen($host, $port, $errno, $errstr, 3)) === FALSE)
echo "$errstr ($errno)";
else {
print 'SUCCESS!<br />';
fwrite($fp, $data);
while (! feof($fp)) {
echo fgets($fp, 4096);
}
fclose($fp);
}
方法2
$host = "localhost";
$port = 6789;
$data = 'test';
if (($socket = socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) === FALSE)
echo "socket_create() failed: reason: " . socket_strerror(socket_last_error());
else
{
echo "Attempting to connect to '$host' on port '$port'...<br>";
if (($result = socket_connect($socket, $host, $port)) === FALSE)
echo "socket_connect() failed. Reason: ($result) " . socket_strerror(socket_last_error($socket));
else {
echo "Sending data...<br>";
socket_write($socket, $data, strlen($data));
echo "OK<br>";
echo "Reading response:<br>";
while ($out = socket_read($socket, 2048)) {
echo $out;
}
}
socket_close($socket);
}
TCP套接字编辑
JAVA到PHP
有很多方法可以做到这一点 我想用来从PHP
if(isset($_GET["user"]) && isset($_GET["pass"])){
echo system("java myjavaprogram . " .$_GET["user"])
// Then args will be an array containing the strings $_GET["user"]
}
和Java程序调用操作命令的任何系统接收命令,并发射行动
public static void main(String [] args) {
String user = args[0]; // user
// etc.. etc
}
您还可以使用卷曲parea使从PHP
的任何请求
if(isset($_GET["user"]) && isset($_GET["pass"])){
$ch = curl_init("http://127.0.0.1:8080/servlet");
$fp = fopen("test.txt", "w");
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_exec($ch);
curl_close($ch);
fclose($fp);
}
我希望我帮助
你能解释一下其中的是java和地方在于PHP运行?在同一台服务器上?为什么你想要一个Java前端应用程序?当两件事情在同一台机器上运行时,他们有更多的沟通方式。 – zapl
php和java在同一台机器上运行 – Larry
修复语法,拼写等 – Prune