我想做一个程序来上传文件在一个页面,并希望导航到另一个页面与该文件的名称。我写这样的代码虽然写了asp.net代码,它显示错误
<%@ Page Title="Home Page" Language="VB" %>
<html>
<head>
<style type="text/css">
.style1
{
width: 100%;
}
.style3
{
width: 185px;
}
.style4
{
width: 129px;
}
</style>
<script language="javascript">
function doc_save() {
document.forms[0].submit;
action = "mynew_page.aspx";
}
doc_save();
</script>
<script language ="vbscript " runat ="server" >
Public Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Call save_click()
End Sub
Public Sub save_click()
Response.Write("Saving...")
End Sub
</script>
</head>
<body>
<form id="form1" runat="server">
<table class="style1">
<tr>
<td class="style4">
<asp:Button ID="back" runat="server" Text="Back" />
</td>
<td class="style3">
<asp:Button ID="save" runat="server" Text="Save" onClick="doc_save()" />
</td>
</tr>
<tr>
<td class="style4">
<asp:Label ID="Label1" runat="server" Text="File Name"></asp:Label>
</td>
<td class="style3">
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
</td>
</tr>
<tr>
<td class="style4">
<asp:Label ID="Label2" runat="server" Text="Description"></asp:Label>
</td>
<td class="style3">
<textarea id="txtarea" name="txtarea" runat ="server" ></textarea></td>
</tr>
<tr>
<td class="style4">
<asp:Label ID="Label3" runat="server" Text="File Upload"></asp:Label>
</td>
<td class="style3">
<asp:FileUpload ID="FileUpload1" runat="server" Width="330px" />
</td>
</tr>
</table>
</form>
</body>
</html>
当我运行该程序它显示像下面的错误。 当然这个代码还没有完成,请你帮忙完成这个。
删除`runat =“server”`将无济于事,因为它是'`。你可以将它转换为一个标准的html按钮(即`