我在为旅行推销员问题正确打印2D数组时遇到问题。我使用输入重定向从文本文件获取输入。该文件包含城市和城市之间的距离的弧线。这是一个小例子。2D Array错误地打印
c 1
c 2
a 1 2 1400
设置我的数组和策划我使用嵌套了城市之间的距离for循环打印出数组,但它看起来像在此之后。
0 1 2 3 4 5
1 0 1400 1800 4000 3500
2 1 0 0 3400 3600
3 1800 1200 0 2300 0
4 4000 3400 2300 0 2100
5 3500 3600 0 2100 0
编辑:我想使它看起来像这样
0 1 2 3 4 5
1 0 1400 1800 4000 3500
2 1400 0 1200 3400 3600
3 1800 1200 0 2300 2700
4 4000 3400 2300 0 2100
5 3500 3600 2700 2100 0
我试图操纵for循环不同的方式,但我似乎无法揣摩出我的问题是在循环或者这是我的代码中的其他地方。
// Sets up the array
int CityArray [6][6] = { {0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0}
};
int main(void) // Takes in a variable number of arguments
{
// Sets a string input for the city
char Cbuffer[32];
char *b = Cbuffer;
size_t cbufsize = 32;
size_t cinput;
// Other vairables
int x = 1; // used to go through the array
int n1, n2, n3, n4, cost; // variables to store the value pulled the cost from the arc
// Reads in the city and sets the prices for each arc
while((cinput = getline(&b, &cbufsize, stdin)) != -1)
{
if (Cbuffer[0] == 'c')
{
// Stores the last element as a digit to CityArray
if (Cbuffer[2] >= '0' && Cbuffer[2] <= '9')
{
CityArray[x][0] = Cbuffer[2] - '0';
int z = CityArray[x][0];
// Flips it
CityArray[0][x] = Cbuffer[2] - '0';
z = CityArray[0][x];
// printf("CityArray[%d] is '%d' \n", x, z);
x++;
}
}
else if (Cbuffer[0] == 'a')
{
int y = 1;
// I know this looks ugly but it's the only way I could think of getting the prices
if ((Cbuffer[6] >= '0' && Cbuffer[6] <= '9') && (Cbuffer[7] >= '0' && Cbuffer[7] <= '9') &&
(Cbuffer[8] >= '0' && Cbuffer[8] <= '9') && (Cbuffer[9] >= '0' && Cbuffer[9] <= '9'))
{
for (x = 1; x < 6; x++)
{
for (y; y < 6; y++)
{ // converts the char to a int
n1 = CityArray[x][6] = Cbuffer[6] - '0';
n2 = CityArray[x][7] = Cbuffer[7] - '0';
n3 = CityArray[x][8] = Cbuffer[8] - '0';
n4 = CityArray[x][9] = Cbuffer[9] - '0';
}
} // sets all converted ints to = cost
cost = (n1 * 1000) + (n2 * 100) + (n3 * 10) + (n4 * 1);
x++;
}
// Checks where the arc is located and plots the distance of the trip
if (Cbuffer[2] == '1')
{
if (Cbuffer[4] == '2')
{
CityArray[1][2] = cost;
CityArray[2][1] = cost;
}
else if (Cbuffer[4] == '3')
{
CityArray[1][3] = cost;
CityArray[3][1] = cost;
}
else if (Cbuffer[4] == '4')
{
CityArray[1][4] = cost;
CityArray[4][1] = cost;
}
else if (Cbuffer[4] == '5')
{
CityArray[1][5] = cost;
CityArray[5][1] = cost;
}
}
else if (Cbuffer[2] == '2')
{
if (Cbuffer[4] == '3')
{
CityArray[2][3] = cost;
CityArray[3][2] = cost;
}
else if (Cbuffer[4] == '4')
{
CityArray[2][4] = cost;
CityArray[4][2] = cost;
}
else if (Cbuffer[4] == '5')
{
CityArray[2][5] = cost;
CityArray[5][2] = cost;
}
}
else if (Cbuffer[2] == '3')
{
if (Cbuffer[4] == '4')
{
CityArray[3][4] = cost;
CityArray[4][3] = cost;
}
else if (Cbuffer[4] == '5')
{
CityArray[4][5] = cost;
CityArray[5][4] = cost;
}
}
else if (Cbuffer[2] == '4')
{
if (Cbuffer[4] == '5')
{
CityArray[4][5] = cost;
CityArray[5][4] = cost;
}
}
}
}
// Prints the array
int i, j;
printf("\n\nThe cost list is:\n\n");
for(i = 0; i < 6;i ++)
{
printf("\n\n");
for(j = 0; j < 6; j++)
{
printf("\t%d", CityArray[i][j]);
}
printf("\n");
}
return 0;
}
“但它看起来像这样。” - 你也可以解释你期望它看起来如何 –
会让我编辑我的问题! – Cheezdue
如果缓冲区不够大,getline将释放现有的缓冲区并分配一个新的缓冲区并返回。所以你不应该通过'Cbuffer',因为这是一个错误来释放它;你不应该测试'Cbuffer [0] =='c''等等,因为该行可能已经被重新分配。相反,你可以设置'b = NULL'来启动,并使用'b [0]'等等(或者避免大量输入,摆脱'b'并使用'char * Cbuffer = NULL;')。 [可能与你的问题没有关系,因为你的文件行数都小于32,但是这是一个滴答作响的时间炸弹] –