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试图创建一个简单的论坛。我将如何在Django 1.9中创建一组命名的URL?该文件说做这样的:Django中的多个参数网址
url(r'^articles/(?P<year>[0-9]{4})/(?P<month>[0-9]{2})/$', views.month_archive),
,我做到了,如:
url(u'^(?P<Name>.*)/(?P<ThreadName>.*)/$', views.thread, name = "thread"),
和views.py:
def thread(request, Name, ThreadName):
board = get_object_or_404(Board, Title = Name)
thread = get_object_or_404(Thread, Title = ThreadName)
context = { "board": board,
"thread": thread,
}
return render(request, "post/board.html", context)
,但我得到一个错误说“没有董事会匹配给定的查询。“,即使董事会存在,我可以到达它的网站/名称,它只会在网站/名称/线程名称失败。
尝试,但我仍然会得到相同的错误。 –