我已经使用此代码显示从数据库中上传的文件,第一个用户需要选择一个文件名,然后他可以看到文件的详细信息(名称+大小+ MIME ..)与“下载“选项,问题是这个页面是重复文件的详细信息4次,名称&大小&下载全部重复,最新的问题是什么?PHP - 显示上传的文件重复
这里是我的代码
$sql = "SELECT r.id, r.name , r.mime, r.size, r.date , s.email
from project_report AS r
JOIN evaluator_supervisor AS e
JOIN student AS s
WHERE (s.PID = $PID AND e.EID1 = '$id' AND s.SID=r.SID) OR (s.PID = $PID AND e.EID2 = '$id' AND s.SID=r.SID) ";
$result = $dbLink->query($sql);
// Check if it was successfull
if($result) {
// Make sure there are some files in there
if($result->num_rows == 0) {
echo '<p>"Sorry, No files uploaded"</p>';
}
else {
// Print the top of a table
echo '<center>';
echo '<table width="90%">
<tr>
<td><b>Name</b></td>
<td><b>Mime</b></td>
<td><b>Size (bytes)</b></td>
<td><b>Date</b></td>
<td><b> </b></td>
<td><b>Feedback</b></td>
</tr>';
// Print each file
while($row = $result->fetch_assoc()) {
echo "
<tr>
<td>{$row['name']}</td>
<td>{$row['mime']}</td>
<td>{$row['size']}</td>
<td>{$row['date']}</td>
<td><a href='Download.php?id={$row['id']}'>Download</a></td>
<td><a href='messege2.php?id={$row['email']}'><img src='mail2.gif'/></a></td>
</tr>";
}
// Close table
echo '</table>';
echo '</center>';
}
echo $ result-> num_rows;输出是什么? –