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我想写查询,并与一个card_nr工作正常。例如:返回列表值与功能
Declare @card_nr as nvarchar(50)
set @card_nr = '704487442952000472'
select
a.times, b.times
from
(select
stat_id, times
from info
where card_nr = @card_nr) as a
left outer join
(select
stat_id, times
from info
where card_nr = @card_nr) as b on a.stat_id = b.stat_id+1
而且我得到了正确的结果:
2014-02-04 11:20:00.000 NULL
2014-02-06 09:44:00.000 2014-02-04 11:20:00.000
2014-02-12 09:59:00.000 2014-02-06 09:44:00.000
2014-02-13 10:31:00.000 2014-02-12 09:59:00.000
2014-02-21 09:49:00.000 2014-02-13 10:31:00.000
我想这样做,每card_nr
从表列表。所以,首先我写的函数:
alter FUNCTION tabletest
(@card_nr as nvarchar(50))
RETURNS smalldatetime
AS BEGIN
Declare @sqldata as smalldatetime
select
@sqldata = b.times
from
(select
stat_id, times
from info where card_nr = @card_nr) as a
left outer join
(select
stat_id, times
from info where card_nr = @card_nr) as b on a.stat_id = b.stat_id + 1
RETURN @datas
END
我试图选择我的查询功能后:
select name, times, dbo.tabletest(card_nr)
from dbo.info
而且我得到不正确的结果:
User1 2014-02-04 11:20:00.000 2014-02-21 09:49:00
User1 2014-02-06 09:44:00.000 2014-02-21 09:49:00
User1 2014-02-12 09:59:00.000 2014-02-21 09:49:00
User1 2014-02-13 10:31:00.000 2014-02-21 09:49:00
User1 2014-02-21 09:49:00.000 2014-02-21 09:49:00
User2 2014-02-14 13:41:00.000 2014-02-28 12:20:00
User2 2014-02-24 11:46:00.000 2014-02-28 12:20:00
User2 2014-02-28 12:20:00.000 2014-02-28 12:20:00
我想得到这个:
User1 2014-02-04 11:20:00.000 NULL
User1 2014-02-06 09:44:00.000 2014-02-04 11:20:00.000
User1 2014-02-13 10:31:00.000 2014-02-12 09:59:00.000
User1 2014-02-13 10:31:00.000 2014-02-12 09:59:00.000
User1 2014-02-21 09:49:00.000 2014-02-13 10:31:00.000
User2 2014-02-14 13:41:00.000 NULL
User2 2014-02-24 11:46:00.000 2014-02-14 13:41:00.000
User2 2014-02-28 12:20:00.000 2014-02-24 11:46:00.000
我会尝试它,但如果我想使用的功能。什么是正确的功能和查询? –
我不想使用一个函数,它们(至少是标量)有时可能会变慢。作为一个经验法则,如果你可以用“普通”sql做到这一点。 – jean
@jean同意,如果可能,我会避免函数调用 – Jayvee