2016-12-06 129 views
0

我有以下表格。基于另一个表中的列值的更新表

表1

Id | Data | Values 
1 | rfsd | 23 
2 | fghf | 45 
3 | rhhh | 23 

表3

Id | Data | Values 
1 | rfsd | 23 
2 | tfgy | 23 

表2

Id | Fields | Counts 
1 | 23  | 0 
2 | 45  | 0 

正如你可以看到,计数字段的值为0我想看 '字段' 列在表2中,然后与表1和表3中的'值'列进行比较,并在'值'字段中存在该值时增加计数。

最终的结果应该显示像这样

Table 2 
Id | Fields | Counts 
1 | 23  | 4 
2 | 45  | 1 

这将是数自23出现四次,45在“价值”表1和表的字段出现一次3.

灿有人请让我知道如何为此编写存储过程。

我已经实现了这样的东西。

WITH t1 AS (
       SELECT VALUES, COUNT(*) AS Count2 FROM Table1 GROUP BY VALUES) 
UPDATE t2 
SET t2.Counts = t1.Count2 
FROM Table2 t2 
JOIN t1 ON t2.Fields=t1.Values; 

WITH t3 AS (SELECT VALUES, COUNT(*) AS Count3 FROM Table3 GROUP BY VALUES) 
UPDATE t2 
SET t2.Counts = t3.Count2 
FROM 
Table2 t2 
JOIN t3 ON t2.Fields=t3.Values; 

当我使用这个存储过程时,它将基于t1表更新t2,然后使用t3表覆盖表t2。

我希望t1和t3列在t2表上同时更新。任何想法如何纠正这个存储过程。

回答

1

您可以使用UNION ALL到组两个表1和3一起(UNION ALL如果你想不交,UNION如果你想删除重复的)

WITH t13 AS (
    SELECT Id, Data, [Values] 
    FROM Table1 
    UNION ALL 
    SELECT Id, Data, [Values] 
    FROM Table3 
), cte AS (
    SELECT 
     [Values], 
     COUNT(*) AS Count2 
    FROM t13 
    GROUP BY 
     [Values] 
) 
UPDATE t2 
SET Counts = cte.Count2 
FROM 
    Table2 t2 JOIN cte ON t2.Fields = cte.[Values]; 
+0

它说,由多个部分组成的标识符“cte.Count2”无法绑定。任何我误会? –

+1

@AduRao固定。 UPDATE中JOIN中的表应该是cte而不是t13。 – DVT

+1

@AduRao我不认为这是要求upvote的正确方法。 http://meta.stackoverflow.com/questions/255583/what-c​​an-i-do-when-getting-we-are-no-longer-accepting-questions-answers-from-th – DVT

1

希望这会有所帮助。

SELECT t2.Id, t2.Fields, COUNT(1) Counts 
FROM Table2 t2 
    LEFT JOIN Table1 t1 ON t2.Fields = t1.[Values] 
    LEFT JOIN Table3 t3 ON t2.Fields = t3.[Values] 
GROUP BY t2.Id, t2.Fields 

如果您需要更新表2,使用以下命令: -

WITH Results AS (
    SELECT t2.Id, COUNT(1) Counts 
    FROM Table2 t2 
     LEFT JOIN Table1 t1 ON t2.Fields = t1.[Values] 
     LEFT JOIN Table3 t3 ON t2.Fields = t3.[Values] 
    GROUP BY t2.Id 
) 
UPDATE t 
SET Counts = r.Counts 
FROM Table2 t 
    JOIN Results r ON t.Id = r.Id; 
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