无法解析占位符“jwt.secret”的字符串值“$ {} jwt.secret”

Question

我已经使用注释配置属性源：

@PropertySource(value = {"classpath:application.properties"})，但我仍然得到错误说Could not resolve placeholder 'jwt.secret' in string value

@PropertySource(value = {"classpath:application.properties"}) 
public class JwtAuthenticationTokenFilter extends AbstractAuthenticationProcessingFilter { 

    @Value("${jwt.header}") 
    private String tokenHeader; 

    public JwtAuthenticationTokenFilter() { 
     super("/**"); 
    } 
} 

调度员的servlet：

<beans xmlns="http://www.springframework.org/schema/beans" 
     xmlns:context="http://www.springframework.org/schema/context" 
     xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns:security="http://www.springframework.org/schema/security" 
     xmlns:jpa="http://www.springframework.org/schema/data/jpa" 
     xmlns:tx="http://www.springframework.org/schema/tx" 
     xsi:schemaLocation=" 
     http://www.springframework.org/schema/beans  
     http://www.springframework.org/schema/beans/spring-beans-4.1.xsd 
     http://www.springframework.org/schema/context 
     http://www.springframework.org/schema/context/spring-context-4.1.xsd 
     http://www.springframework.org/schema/mvc 
     http://www.springframework.org/schema/mvc/spring-mvc-4.1.xsd 
     http://www.springframework.org/schema/security 
     http://www.springframework.org/schema/security/spring-security-4.1.xsd 
     http://www.springframework.org/schema/data/jpa 
     http://www.springframework.org/schema/data/jpa/spring-jpa.xsd 
     http://www.springframework.org/schema/tx 
     http://www.springframework.org/schema/tx/spring-tx.xsd"> 

    <context:component-scan base-package="com.rsc."/> 
    <mvc:annotation-driven /> 

    <mvc:resources mapping="/resources/**" location="/resources/"/> 

    <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource"> 
     <property name="basenames"> 
      <list> 
       <value>classpath:validation</value> 
      </list> 
     </property> 
    </bean> 

<!-- <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> 
     <property name="locations"> 
      <list> 
       <value>classpath:application.yml</value> 
      </list> 
     </property> 
    </bean>--> 

    <!-- <security:authentication-manager alias="authenticationManager"> 
     <security:authentication-provider user-service-ref="userDetailsServiceImpl"> 
      <security:password-encoder ref="encoder"></security:password-encoder> 
     </security:authentication-provider> 
    </security:authentication-manager>--> 

    <!--<bean id="userDetailsServiceImpl" class="com.rsc.service.UserDetailsServiceImpl"></bean>--> 

    <bean id="JwtAuthenticationTokenFilter" class="com.rsc.security.JwtAuthenticationTokenFilter"> 
     <property name="authenticationManager" ref="authenticationManager" /> 
     <property name="authenticationSuccessHandler" ref="jwtAuthenticationSuccessHandler" /> 
    </bean> 

    <security:authentication-manager alias="authenticationManager"> 
     <security:authentication-provider ref="jwtAuthenticationProvider" /> 
    </security:authentication-manager> 

    <bean id="encoder" class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder"> 
     <constructor-arg name="strength" value="11"/> 
    </bean> 

    <!-- Configure the data source bean --> 
    <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> 
     <property name="driverClassName" value="${jdbc.driverClassName}"/> 
     <property name="url" value="${jdbc.url}"/> 
     <property name="username" value="${jdbc.username}"/> 
     <property name="password" value="${jdbc.password}"/> 
    </bean> 

    <!-- Configure the entity manager factory bean --> 
    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> 
     <property name="dataSource" ref="dataSource"/> 
     <property name="packagesToScan" value="com.rsc.model"/> 
     <property name="jpaVendorAdapter"> 
      <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/> 
     </property> 
     <property name="jpaProperties"> 
      <props> 
       <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> 
       <prop key="hibernate.show_sql">true</prop> 
       <prop key="hbm2ddl.auto">create</prop> 
       <prop key="hibernate.id.new_generator_mappings">false</prop> 
      </props> 
     </property> 
    </bean> 

    <!-- Configure the transaction manager bean --> 
    <bean id="transactionManager" 
      class="org.springframework.orm.jpa.JpaTransactionManager"> 
     <property name="entityManagerFactory" ref="entityManagerFactory"/> 
    </bean> 

    <!-- Enable annotation driven transaction management --> 
    <tx:annotation-driven/> 

    <jpa:repositories base-package="com.rsc.repository"/> 

    <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
     <property name="prefix" value="/WEB-INF/views/"/> 
     <property name="suffix" value=".jsp"/> 
    </bean> 
</beans> 

应用程序属性：

jdbc.driverClassName=com.mysql.jdbc.Driver 
jdbc.url=jdbc:mysql://localhost:3306/rs_education 
jdbc.username=admin 
jdbc.password=admin 

jwt: 
    header: Authorization 
    secret: my-very-secret-key 
logging: 
    level: 
    org.springframework.security: DEBUG 
server: 
    port: 8888 
spring: 
    resources: 
    chain: 
     enabled: true 
management: 
    security: 
    enabled: true # set to false to disable 'default' Spring Boot security 

Answer 1

你不能做到这一点：

jwt: 
    header: Authorization 
    secret: my-very-secret-key 

它应该是这样的：

jwt.header=Authorization 
jwt.secret=my-very-secret-key 

Answer 2

作为文档状态，可以使用YAML，但你必须打电话给你的文件application.yml而不是application.properties 。

您还必须将snakeyaml添加到您的依赖项中。