PHP：如何启动一个独立进程？

Question

目前我的解决办法是：

exec('php file.php >/dev/null 2>&1 &'); 

和file.php

if (posix_getpid() != posix_getsid(getmypid())) 
    posix_setsid(); 

有什么方法可以让我这样做只是以exec？

Answer 1

不，这不能与exec()（也不shell_exec()或system()）

---

做。如果你已经安装了pcntl extension这将是：

function detached_exec($cmd) { 
    $pid = pcntl_fork(); 
    switch($pid) { 
     // fork errror 
     case -1 : return false 

     // this code runs in child process 
     case 0 : 
      // obtain a new process group 
      posix_setsid(); 
      // exec the command 
      exec($cmd); 
      break; 

     // return the child pid in father 
     default: 
      return $pid; 
    } 
} 

这样称呼它：

$pid = detached_exec($cmd); 
if($pid === FALSE) { 
    echo 'exec failed'; 
} 

// do some work 

// kill child 
posix_kill($pid, SIGINT); 
waitpid($pid, $status); 

echo 'Child exited with ' . $status; 

Answer 2

提供您的当前用户有足够的权限这样做，这应该可能与exec和类似：

/* 
/Start your child (otherscript.php) 
*/ 
function startMyScript() { 
    exec('nohup php otherscript.php > nohup.out & > /dev/null'); 
} 

/* 
/Kill the script (otherscript.php) 
/NB: only kills one process at the time, otherwise simply expand to 
/loop over all complete exec() output rows 
*/ 
function stopMyScript() { 
    exec('ps a | grep otherscript.php | grep -v grep', $otherProcessInfo); 
    $otherProcessInfo = array_filter(explode(' ', $otherProcessInfo[0])); 
    $otherProcessId = $otherProcessInfo[0]; 
    exec("kill $otherProcessId"); 
} 

// ensure child is killed when parent php script/process exits 
register_shutdown_function('stopMyScript'); 

startMyScript();