2013-07-08 45 views
1

所以我有一个功能,像这样:C#WebResponse流丢失字节?

private String SendRequest(String jsonRequest) 
    { 
     WebRequest webRequest = WebRequest.Create(_url); 
     byte[] paramBytes = Encoding.UTF8.GetBytes(jsonRequest); 
     byte[] responseBytes; 

     webRequest.Method = "POST"; 
     webRequest.ContentType = "application/json"; 
     webRequest.ContentLength = paramBytes.Length; 
     webRequest.Headers.Add("X-Transmission-Session-Id", _sessionId); 


     using (Stream oStream = webRequest.GetRequestStream()) 
     { 
      oStream.Write(paramBytes, 0, paramBytes.Length); 
     } 

     WebResponse webResponse = webRequest.GetResponse(); 

     using (Stream iStream = webResponse.GetResponseStream()) 
     { 
      responseBytes = new byte[webResponse.ContentLength]; 
      iStream.Read(responseBytes, 0, (int) webResponse.ContentLength); 
     } 

     return Encoding.UTF8.GetString(responseBytes); 
    } 

的问题是,在iStream.Read()阶段,一些字节都将丢失。使用wireshark显示所有的字节被发送到这台机器,但是.net在这个路上的某处丢失了。例如,在我当前的调试会话中,其中webResponse.ContentLength = 4746字节[3949]至字节[4745]均为0,但它们应该填充。因此,UTF8 JSON字符串提前切断,我无法对JSON进行反序列化。

我认为代码非常清晰,我看不到错在哪里去释放这些字节。

感谢您的帮助!

回答

1

我使用的StreamReader代替:)

private String SendRequest(String jsonRequest) 
    { 
     WebRequest webRequest = WebRequest.Create(_url); 
     byte[] paramBytes = Encoding.UTF8.GetBytes(jsonRequest); 
     String jsonResponse; 

     webRequest.Method = "POST"; 
     webRequest.ContentType = "application/json"; 
     webRequest.ContentLength = paramBytes.Length; 
     webRequest.Headers.Add("X-Transmission-Session-Id", _sessionId); 


     using (Stream oStream = webRequest.GetRequestStream()) 
     { 
      oStream.Write(paramBytes, 0, paramBytes.Length); 
      oStream.Close(); 
     } 

     WebResponse webResponse = webRequest.GetResponse(); 

     using (Stream iStream = webResponse.GetResponseStream()) 
     { 
      StreamReader reader = new StreamReader(iStream, Encoding.UTF8); 
      jsonResponse = reader.ReadToEnd(); 
      reader.Close(); 
      iStream.Close(); 
     } 

     return jsonResponse; 
    }