0
所以,我有这个方法,并在最后一行,它试图得到samAccountName,它抛出我一个COM异常,这让我疯狂。AD查询,服务器不可操作
有什么想法?
public User FindUsername(string samAccountName, string groupDisplayName)
{
using (DirectoryEntry searchRoot = new DirectoryEntry(ldapf, ldapu, ldapp))
{
using (DirectorySearcher searcher = new DirectorySearcher(searchRoot))
{
searcher.Asynchronous = false;
searcher.PropertiesToLoad.Add("SAMAccountName");
searcher.PropertiesToLoad.Add("displayName");
searcher.PropertiesToLoad.Add("uSNChanged");
searcher.PropertiesToLoad.Add("member");
searcher.PropertiesToLoad.Add("co");
searcher.PropertiesToLoad.Add("company");
searcher.PropertiesToLoad.Add("mail");
searcher.Filter = String.Format("(SAMAccountName={0})", samAccountName);
searcher.SearchScope = SearchScope.Subtree;
searcher.PageSize = 1000;
SearchResult result = searcher.FindOne();
ResultPropertyCollection resultPropColl = result.Properties;
Object memberColl = resultPropColl["member"];
using (DirectoryEntry memberEntry = new DirectoryEntry("LDAP://" + memberColl, ldapu, ldapp))
{
try
{
System.DirectoryServices.PropertyCollection userprops = memberEntry.Properties;
object obVal = userprops["SAMAccountName"].Value;
什么是例外? – 2012-04-03 11:37:08
服务器不可操作COMException。 – 2012-04-03 11:40:40
检查你的属性,SAMAccountName应该是sAMAccountName(链接:http://msdn.microsoft.com/en-us/library/windows/desktop/ms679635(v=vs.85).aspx) – jwillmer 2012-04-03 11:41:41