这就是我如何创建search option does not appear on the page这个线程和罚款我必须工作,但这是我应该如何查找表中的3个领域,它以任何方式工作。同时搜索三个区域,
if($stmt = $this->mysqli->prepare('SELECT `navn`, `link`, `img`, `omrade` FROM `ordblindtest` WHERE `navn` LIKE "%" . $navn . "%" OR `omrade` LIKE "%" . $omrade . "%" OR `sogord` LIKE "%" . $sogord . "%"'))
{
$stmt->bind_param('sss', $navn, $omrade, $sogord);
$navn = $_POST["sogord"];
$omrade = $_POST["sogord"];
$sogord = $_POST["sogord"];
...
}
问题是,我得到这个错误:
Error on: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '. $navn . "%", OR
omrade
LIKE "%" . $omrade . "%", ORsogord
LIKE "%" . $sog' at line 1
我不明白为什么它似乎有错误。为什么我收到错误?
你注入的变量到你的查询。这不是如何使用准备好的语句。 – h2ooooooo
[搜索选项没有出现在页面上]可能的重复(http://stackoverflow.com/questions/21407213/search-option-does-not-appear-on-the-page) – MichaelRushton