通过COUNT搜索（*）

Question

我试图让每个人的技能数量都达到所有人的名字！所以一切都很好，但问题是如何搜索一个有'2'技能的人呢？

SELECT FULLNAME, TeamNAME, COUNT(*) AS NoSkills 
FROM [Skills Matrix].[dbo].[PeopleSkills] AS PS, [Skills Matrix].[dbo].[People] AS P, [Skills Matrix].[dbo].[Teams] AS T 
WHERE PS.FK_People = P.ID AND P.FK_TEAM = T.ID AND NoSkills LIKE '2' 
GROUP BY FULLNAME, TeamNAME, NoSkills 

此输出我有：

能不能帮我请！

Answer 1

GROUP BY FULLNAME, TeamNAME 
HAVING COUNT(*) = 2 

Answer 2

您不应该按您在选择列表中创建的别名进行分组。从GROUP BY删除NoSkills。另外，如果要过滤聚合函数的值（例如COUNT），则应使用HAVING子句（而不是WHERE）。

SELECT FULLNAME, TeamNAME, COUNT(*) AS NoSkills 
FROM [Skills Matrix].[dbo].[PeopleSkills] AS PS, [Skills Matrix].[dbo].[People] AS P, [Skills Matrix].[dbo].[Teams] AS T 
WHERE PS.FK_People = P.ID AND P.FK_TEAM = T.ID 
GROUP BY FULLNAME, TeamNAME 
HAVING COUNT(*) = 2 

Answer 3

通过子句删除NoSkills从基。