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我已经创建了下面提到的SQL的HQL,但我无法通过Criteria和Sub查询来执行它。请帮助我通过Criteria执行以下查询(SQL & HQL)。感谢提前 ...标准查询多对多
SQL:
SELECT * FROM app_interface ain WHERE ain.id IN (SELECT ai.id FROM app_interface ai INNER JOIN app_module_interface ami ON ami.interface_id = ai.id INNER JOIN app_module am ON am.id = ami.module_id WHERE am.id = :id
HQL:
FROM AppModule oam WHERE oam.id IN(SELECT am.id FROM AppModule am INNER JOIN am.appRoles ar WHERE ar.id = :id)
通过所需的标准... .. ?????
场景:
public class AppModule implements java.io.Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id", unique = true, nullable = false)
private Integer id;
@ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "appModules")
private Set<AppRole> appRoles = new HashSet<AppRole>(0);
}
公共类AppRole实现java.io.Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id", unique = true, nullable = false)
private Integer id;
@ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@OrderBy("name")
@JoinTable(name = "app_role_module", joinColumns = {
@JoinColumn(name = "role_id", nullable = false, updatable = false)}, inverseJoinColumns = {
@JoinColumn(name = "module_id", nullable = false, updatable = false)})
private Set<AppModule> appModules = new HashSet<AppModule>(0);
}
我是新来的Hibernate,但不是太新:)。但任何如何......谢谢 –
这个答案是关于IN运算符。但我也要求'FROM AppModule oam WHERE oam.id NOT IN(SELECT AM.ID FROM AppModule am IN JOIN IN am.appRoles ar WHERE ar.id =:id)' –
请参阅我编辑的答案。 –