Linq JObject查询

Question

我有一些jobject和jarray linq查询问题。我得到这个错误：

Unable to cast object of type 'Newtonsoft.Json.Linq.JObject' to type  'Newtonsoft.Json.Linq.JArray'. 

我的代码：

string fetchResult = JsonConvert.SerializeObject(sidebar, Formatting.Indented); 
JObject rss = JObject.Parse(fetchResult); 

var jsonModel = from item in (JArray)rss["RegistrationCase"] 
         select new DataList 
         { 
          RegistrationTypeName = item["RegistrationTypeName"].Value<string>(), }; 

如果我删除（Jarray）我得到：在Newtonsoft.Json.Linq.JProperty无法访问的孩子的价值。 JSON，jobject：例如：我想要RegistrationTypeName，FirstName和JournalNumber的值。

{ 
"Status": null, 
"RegistrationCase": { 
"RegistrationTypeName": " ", 
"ExpireDate": null, 
"PersonId": 7, 
"Person": { 
    "FirstName": " ", 
    "GenderValue": 2, 
    "Gender": 2, 
}, 
"UserId": 7, 
"User": { 
    "UserName": "NO-DOM\\wme", 
    "LastName": null, 
    "Id": 7, 
}, 
"Transactions": [], 
"Comments": [], 
"CustomData": [ 
    { 
    "Key": "JournalNumber", 
    "Value": "0654-84148-00000-25", 
    "Id": 3, 
    }, 
    { 
    "Key": "IsConsentGiven", 
    "Value": "False", 
    "Id": 4, 
    }, 
    { 
], 
"FileId": null, 
"File": null, 
"Id": 7, 
} 
} 

Answer 1

u能获取这些值直接，如：

var RegistrationTypeName = rss["RegistrationCase"]["RegistrationTypeName"]; 
    var FirstName = rss["RegistrationCase"]["Person"]["FirstName"]; 
    var JournalNumber = rss["RegistrationCase"]["CustomData"][0]["Value"];