的Oracle SQL：添加行选择结果

Question

说我有一个列的表格：id, group_id, type, val
从选择一些示例数据：
1, 1, 'budget', 100
2, 1, 'budget adjustment', 10
3, 2, 'budget', 500
4, 2, 'budget adjustment', 30

我想要的结果看起来像
1, 1, 'budget', 100
2, 1, 'budget adjustment', 10
5, 1, 'budget total', 110
3, 2, 'budget', 500
4, 2, 'budget adjustment', 30
6, 2, 'budget total', 530

请指教，
感谢。

Answer 1

由于@Serpiton建议，看来你真的需要的功能，是小计添加到您的能力结果集，这表明rollup是您需要的。用法是这样的：

SELECT id, 
     group_id, 
     coalesce(type, 'budget total') as type, 
     sum(val) as val 
FROM  your_table 
GROUP BY ROLLUP (group_id), id, type 

Answer 2

这将得到您需要的两个添加行，但不是您想要的ID和类型的值。

甲骨文例子：http://docs.oracle.com/cd/B19306_01/server.102/b14223/aggreg.htm

Select id, group_id, type as myType, sum(val) as sumVal 
FROM Table name 
Group by Grouping sets ((id, group_id, type, val), (group_ID)) 

Answer 3

可以使用UNION ALL更行添加到原来的选择。

select group_id,type,val from tableA 
union all 
select group_id, 'budget total' as type,sum(val) as val from tableA group by group_id,type 

要显示正确的顺序和id，你可以使用嵌套选择

select rownum, group_id,type,val from (select group_id,type,val from tableA 
union all 
select group_id, 'budget total' as type,sum(val) as val from tableA group by group_id,type) order by group_id asc 

Answer 4

with foo as 
(select 1 group_id, 'budget' type, 100 val 
    from dual 
    union 
    select 1, 'budget adjustment', 10 
    from dual 
    union 
    select 2, 'budget', 500 
    from dual 
    union 
    select 2, 'budget adjustment', 30 
    from dual) 
SELECT rank() over(order by type, group_id) rk, 
     group_id, 
     nvl(type, 'budget total') as type, 
     sum(val) as val 
    FROM foo 

group by Grouping sets((group_id, type, val),(group_id)) 

它就是xQbert后的延续，有ID值！