PIL image.open（）不适用于我的.png

Question

我使用PIL打开图像以提取几位并将它们写入字符串。它应该是，这个代码将过滤除了那些，有代码（R < = 1 & & G < = 1 & & B < = 1），并拿走每种颜色的最后一位。问题是它不起作用。

from PIL import Image 
def extract_bits(color, bitmask): 
    bitmask_len = len(bin(bitmask)[2:]) 
    extracted_bits = bin(color & bitmask)[2:] 
    extracted_bits = '0' * (bitmask_len - len(extracted_bits)) + extracted_bits 

    return extracted_bits 

if __name__ == '__main__': 
    img = Image.open('IMG_0707png') 
    pixels = list(img.getdata()) 

    bits = '' 
    for i in range(0, len(pixels), 1): 
     r = pixels[i][0] 
     g = pixels[i][1] 
     b = pixels[i][2] 

     if not (r <= 1 and g <= 1 and b <= 1): continue 

     bits += extract_bits(r, 0x1) 
     bits += extract_bits(g, 0x1) 
     bits += extract_bits(b, 0x1) 

    bits += '0' * (8 - len(bits) % 8) 

    text = '' 
    for i in range(0, len(bits), 8): 
     text += chr(int(bits[i:i+8], 2)) 
    print text 

我环顾这个问题，发现解决方案在我的情况下不起作用。 img = Image.open(open('IMG_0707.png', 'rb')) 在这两种情况下，我得到

File "<stdin>, line 1, in <module>" 
File "<string>" line11, im <module> 
File "c:\python27\lib\site-packages\PIL\Image.py", line 1980, in open 
raise IOError("cannot identify image file") 
IOError: cannot identify image file 

我也试过，没有运气指定确切路径。

img = Image.open(open("IMG_0707.png", 'rb')) 
img = Image.open(open("c:\python27\IMG_0707.png", 'rb')) 
img = Image.open(open("c:/python27/IMG_0707.png", 'rb')) 

依此类推。我会很感激任何帮助。 Image, im trying to open

Answer 1

该PNG已损坏。这里是ImageMagick的说的话：

$ convert IMG_0707.png IMG_0707-new.png 
convert: IHDR: CRC error `IMG_0707.png' @ error/png.c/MagickPNGErrorHandler/1309. 
convert: corrupt image `IMG_0707.png' @ error/png.c/ReadPNGImage/3294. 
convert: missing an image filename `IMG_0707-new.png' @ error/convert.c/ConvertImageCommand/3011. 

Answer 2

import Image 
try: 
    from StringIO import StringIO 
except ImportError: 
    from io import StringIO 
import numpy as np 

im = Image.open(StringIO(raw_data)) 

您好我有同样的问题，这是解决方案 raw_data：在我的情况下，它是的base64解码PNG文件