C++列表迭代不访问列表的内容

Question

可视化：
NTlist：[NTstring，RHSlist] < - > [NTstring，RHSlist] < - > [NTstring，RHSlist] ...

Ntlocation“点”，比如说，中间链接^（上面），因为这里的NTstring匹配我正在搜索的内容。

我想要做什么：
使用NTlocation “指针” 我想访问和修改此处的RHSlist。

问题：
Debugger shows RHSlist data being put into NTlocation

But I want RHSlist data to be in element of NTlist

非常感谢您的帮助！

编辑。每个请求添加代码。再次感谢！

typedef struct RHSnode { 
    token_type type; 
    string token; 
} RHSnode; 

typedef struct NTnode { 
    token_type type; 
    string token; 
    list<RHSnode> RHSlist; 
} NTnode; 

int function { 
    list<NTnode> NTlist; 
    list<NTnode>::iterator NTlocation; 

    freopen("example.txt", "r", stdin); 
    t_type = getToken(); //this function gets tokens from txt file above 
    // code has been simplified for your viewing pleasure 
    // but basically NT.list is created for each token listed at start of 
    // text file in the following manner. (This works fine) 
    NTnode entry; 
    entry.token = string(current_token); 
    NTlist.push_back(entry); 
    t_type = getToken(); 

    // loop until all tokens are read 
    { 
    t_type = getToken(); 
    string NTstring = string(current_token); 
    NTlocation = searchNTList(NTstring, NTlist); 

    RHSnode entry; 
    entry.token = string(current_token); 

    //****Here is the problem: 
    NTlocation->RHSlist.push_back(entry);    

    } 

    return 1; 
} 

list<NTnode>::iterator searchNTList(string NTstring, list<NTnode> &NTlist){ 
    list<NTnode>::iterator NTlocation = NTlist.end(); //"past-the-end"  indications search failure 
    list<NTnode>::iterator iterator = NTlist.begin(); 

    for (; iterator != NTlist.end() ; iterator++){ 

    if (iterator->token.compare(NTstring) == 0){ 
     NTlocation = iterator; 
     break; 
    } 

    } 
    return NTlocation; 
} 

Answer 1

最低限度：

list<NTnode>::iterator searchNTList(string NTstring, list<NTnode> NTlist){ 

这将返回一个迭代器的NTlist本地副本。你可能想通过const引用传递NTlist。