访问：IIF语句和COUNT

Question

，这里是我的代码工作的感谢Jim B：

SELECT IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) AS [Occurrence Code], Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) 
FROM [Lab Occurrence Form] 
WHERE ((([Lab Occurrence Form].[Occurrence Date]) Between [Forms]![Meeting_Reasons_Frequency]![Text4] And [Forms]![Meeting_Reasons_Frequency]![Text2])) 
GROUP BY [Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] 
HAVING ((Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]))<>0) 
ORDER BY Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) DESC; 

它返回：

1.1 Specimen Mislabeled 159 
1.3 QNS-Quantity Not Sufficient 84 
1.9 QNS- Specimen Spilled in transit 72 
1.6 Test Requisition Missing 17 
1.11 Other 3 
1.11 Other 3 
1.1 Specimen Mislabeled-new ID # given 2 
1.11 Other 2 
1.11 Other 2 
1.1 Specimen Mislabeled & 1.6 Test Requisition Missing 1 
1.11 Other 1 
1.11 Other 1 
1.11 Other 1 
1.11 Other 1 
1.11 Other 1 
? Nothing in comments portion of QuikLab 1 
1.11 Other 1 
1.11 Other 1 
1.4 Tests Missed/ Wrong Test Ordered 1 
1.4 Tests Missed/Wrong Test Ordered 1 
1.6 Test Requisition Missing & 1.7 Specimen Lost 1 
1.8 Specimen not handled/processed correctly & 1.10 Operator Error(?) 1 
1.11 Other 1 
1.11 Other 1 

这正是我需要的但是，有一个轻微的事情关闭。我需要它计数'1.11其他'

我该怎么做呢？换句话说，这是输出我需要：

? Nothing in comments portion of QuikLab 1 
1.1 Specimen Mislabeled 159 
1.1 Specimen Mislabeled & 1.6 Test Requisition Missing 1 
1.1 Specimen Mislabeled-new ID # given 2 
1.11 Other 19 
1.3 QNS-Quantity Not Sufficient 84 
1.4 Tests Missed/ Wrong Test Ordered 1 
1.4 Tests Missed/Wrong Test Ordered 1 
1.6 Test Requisition Missing 17 
1.6 Test Requisition Missing & 1.7 Specimen Lost 1 
1.8 Specimen not handled/processed correctly & 1.10 Operator Error(?) 1 
1.9 QNS- Specimen Spilled in transit 72 

，你可以看到有一种1.11 Other只有一个发生19

JIM B的总数表明，这：

Use your IIF statement all the way through your group by and having clauses – Jim B 

但我不明白如何实现它。请帮忙！

Answer 1

更多的是SQL Server的家伙，所以我不知道如果你能做到这一点，但有你的尝试：

SELECT IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) AS [Occurrence Code], Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) 
FROM [Lab Occurrence Form] 
WHERE ((([Lab Occurrence Form].[Occurrence Date]) Between [Forms]![Meeting_Reasons_Frequency]![Text4] And [Forms]![Meeting_Reasons_Frequency]![Text2])) 
GROUP BY IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) 
HAVING ((Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]))<>0) 
ORDER BY Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) DESC; 

Answer 2

您在列语句中使用的解决方案还需要包含在计数函数中。因为您希望根据修订的列数据而不是原始列数据进行计数。

Answer 3

也许这样的事情？

SELECT IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) AS [Occurrence Code], Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) 
FROM [Lab Occurrence Form] 
WHERE ((([Lab Occurrence Form].[Occurrence Date]) Between [Forms]![Meeting_Reasons_Frequency]![Text4] And [Forms]![Meeting_Reasons_Frequency]![Text2])) 
GROUP BY IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) 
HAVING ((Count(IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)])))<>0) 
ORDER BY Count(IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)])) DESC;