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此问题可能看起来像许多其他人的副本,但我无法在任何地方找到我的错误。Node.js async.each引发“回调已被调用”
问题是,async.each引发“回调已被调用”。这里的片段(我称为异步回调done
,所以它不会在我的代码的其它回调感到困惑):
async.each(this.requirements, (requirement, done) => {
// That thing here passes the result as a callback
requirement.callback((result) => {
if (!result) {
// requirement not passed -> return error
done(true); // LINE 42
} else {
done(); // LINE 44
}
}, data, params, bot);
}, (err) => { // 'done' callback
log.info('handler',
`Handler '${this.label}' ${err ? 'failed' : 'succeeded'}`);
// if any requirement did not pass, do not execute handler callback
if (!err) this.callback(data, params, bot);
});
这里是它的堆栈跟踪:
C:\Users\samuel\Code\node\sk22tgjs\node_modules\async\dist\async.js:837
if (fn === null) throw new Error("Callback was already called.");
^
Error: Callback was already called.
at C:\Users\samuel\Code\node\sk22tgjs\node_modules\async\dist\async.js:837:34
at requirement.callback (C:\Users\samuel\Code\node\sk22tgjs\node_modules\telegramjs\core\handler.js:44:11)
at Requirement.exports.command.Requirement.callback (C:\Users\samuel\Code\node\sk22tgjs\node_modules\telegramjs\telegram\requires.js:21:5)
at async.each (C:\Users\samuel\Code\node\sk22tgjs\node_modules\telegramjs\core\handler.js:39:19)
at C:\Users\samuel\Code\node\sk22tgjs\node_modules\async\dist\async.js:2953:18
at replenish (C:\Users\samuel\Code\node\sk22tgjs\node_modules\async\dist\async.js:872:19)
at C:\Users\samuel\Code\node\sk22tgjs\node_modules\async\dist\async.js:878:27
at C:\Users\samuel\Code\node\sk22tgjs\node_modules\async\dist\async.js:840:18
at requirement.callback (C:\Users\samuel\Code\node\sk22tgjs\node_modules\telegramjs\core\handler.js:44:11)
at Requirement.callback (C:\Users\samuel\Code\node\sk22tgjs\node_modules\telegramjs\core\requires.js:19:5)
有趣事情是,只有done(true)
被调用才会发生问题。然而,在第44行出现错误,而不是42
您还可以看到在GitHub上腐败的代码,尤其是testing
分支:https://github.com/22sk/telegramjs
在此先感谢。
https://github.com/22sk/telegramjs/blob/master/telegram/requires.js#L16缺少return语句,以防止从'获取调用两次result'? (为什么堆栈跟踪指向21行) –
啊,该死的。没有想到那么远,谢谢。你会把它作为答案吗? – 22samuelk
为了清楚起见,摆脱了箭头功能 –