与单列作为结果，对多个变量赋值

我有一个表像这样与单列作为结果，对多个变量赋值

+----+------+ 
| ID | Name | 
+----+------+ 
| 0 | Foo | 
| 1 | Bar | 
+----+------+

基于我想根据每一行来计算的排名表中的行，让喜欢

SELECT *, [calculation] AS ranking 
FROM table 
ORDER BY ranking DESC

查询

将返回类似

+----+------+---------+ 
| ID | Name | Ranking | 
+----+------+---------+ 
| 0 | Bar |  3 | 
| 1 | Foo |  1 | 
+----+------+---------+

我的问题是，我需要每行执行多个任务W¯¯没有得到更多的专栏;基本上类似

@ranking:= 0 
IF(Name LIKE $firstTerm, @ranking := @ranking + 1, @ranking := @ranking) 
IF(Name LIKE $secondTerm, @ranking := @ranking + 1, @ranking := @ranking) 
IF(Name LIKE $thirdTerm, @ranking := @ranking + 1, @ranking := @ranking)

对于每一行，使得在端部余为每个条目是0，1，2或3个作为一个额外的列在我的表

编辑：在理论动态生成的像

SELECT * 
FROM table 
ORDER BY SUM(
    CASE 
    WHEN 
     (NAME LIKE $firstTerm AND NAME NOT LIKE $secondTerm AND NAME NOT LIKE $thirdTerm) 
     OR (NAME NOT LIKE $firstTerm AND NAME LIKE $secondTerm AND NAME NOT LIKE $thirdTerm) 
     OR (NAME NOT LIKE $firstTerm AND NAME NOT LIKE $secondTerm AND Name LIKE $thirdTerm) THEN 1 
    WHEN (Name LIKE $firstTerm AND Name LIKE $secondTerm AND Name NOT LIKE $thirdTerm) 
    OR (Name NOT LIKE $firstTerm AND Name LIKE $secondTerm AND Name LIKE $thirdTerm) THEN 2 
    WHEN (Name LIKE $firstTerm AND Name LIKE $secondTerm AND Name LIKE $thirdTerm) THEN 3 
    ELSE 0 
) DESC;

会按预期工作，但你可以想象，如果我们有超过3个术语，这将是怎么回事！

来源

2016-11-26 RoiEX

告诉我们更多关于计算 – Strawberry

这应该是多个LIKE比较的，因此，它有更多的比赛，越高它的排名 – RoiEX

@Strawberry我编辑我的问题是更正确的（加了LIKE语句例子） – RoiEX

SELECT *, 
    IF(Name like $firstTerm, 1, 0) + 
    IF(Name like $secondTerm, 1, 0) as Ranking 
    FROM table ORDER BY Ranking DESC;

但是，如果数据集变大，计算复杂，使用搜索引擎（elasticsearch，SOLR）是会更有效，更灵活。

来源

2016-11-26 11:23:52 tzunghaor

这正是我所需要的！谢谢！应该有这个想法！ – RoiEX

与单列作为结果，对多个变量赋值

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