SQL命令检索嵌套在

Question

列

列表考虑一下这个表：

Employees Segment  Function  
John  Retail  Sales 
Peter  Retail  Sales 
Lucas  Retail  Sales 
Steve  Retail  Sales 
Maria  Retail  Sales 

我希望得到的名单，像这样：（别名第一列）

'Area' 'Employees' 
Retail John,Lucas,Maria 
Sales John,Lucas,Maria 

要组装查询我有只有员工名单。所以条件应该是这样的：

WHERE Employees IN('John','Maria','Lucas'). 

我只有访问查询数据库。

我可以在一排安装的员工名单，像这样：

SELECT 
Employees = Stuff(
    (SELECT N', ' + Employees FROM table A WHERE Employees 
     IN('John','Maria','Lucas') FOR XML PATH(''),TYPE) 
    .value('text()[1]','nvarchar(max)'),1,2,N''); 

，我还可以通过合并细分和功能类似这样的创建“区域”：

SELECT Segment 'Area' FROM table 
WHERE Employees IN('John','Maria','Lucas') 
UNION SELECT Function 'Area' FROM table 
WHERE Employees IN('John','Maria','Lucas') 

我会喜欢只是合并使用的东西作为UNION这两个选择，就像这样：

SELECT 
    Employees = Stuff(
     (SELECT N', ' + Employees FROM table A WHERE Employees 
      IN('John','Maria','Lucas') FOR XML PATH(''),TYPE) 
     .value('text()[1]','nvarchar(max)'),1,2,N'') 
    UNION 
    SELECT Segment 'Area' FROM table 
    WHERE Employees IN('John','Maria','Lucas') 
    UNION SELECT Function 'Area' FROM table 
    WHERE Employees IN('John','Maria','Lucas') 

结果出来了，如：

'Employees' 
John,Maria,Lucas 
Retail 
Sales 

也许我错过了关于UNION语法的一些细节，或者它并不像我期望的那么简单。

Answer 1

你仍然可以使用你的UNION，你只需要做两次STUFF（）。

SELECT DISTINCT Segment AS 'Area' 
       , Stuff((SELECT N', ' + Employees 
         FROM table A 
         WHERE Employees IN('John','Maria','Lucas') 
         FOR XML PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') FROM table 
WHERE Employees IN ('John','Maria','Lucas') 
UNION 
SELECT DISTINCT Func AS 'Area' 
      , Stuff((SELECT N', ' + Employees 
        FROM table A 
        WHERE Employees IN('John','Maria','Lucas') 
        FOR XML PATH(''),TYPE).value('text()[1]','nvarchar(max)'),1,2,N'') FROM table 
WHERE Employees IN ('John','Maria','Lucas') 

Answer 2

希望，这将满足您的要求。

尝试它在sqlfiddle，工作正常。

SELECT a.Fun Area, 
     SUBSTRING(d.Employees,1, LEN(d.Employees) - 1) Employees 
FROM(SELECT DISTINCT Fun FROM test_so) a 
     CROSS APPLY 
     (SELECT [Employees] + ', ' FROM test_so AS B WHERE A.Fun = B.Fun FOR XML PATH('') 
     ) D (Employees)  
UNION 
SELECT a.Segment Area, SUBSTRING(d.Employees,1, LEN(d.Employees) - 1) Employees 
FROM(SELECT DISTINCT Segment FROM test_so) a 
     CROSS APPLY 
     (SELECT [Employees] + ', ' FROM test_so AS B WHERE A.Segment = B.Segment FOR XML PATH('') 
     ) D (Employees)