2015-03-25 113 views
0

我正试图将2张照片保存到我的MySQL数据库。我只能看到数据库中2张照片中的一张(即其名称),但我看到我存储照片的文件夹中的2张照片。 (附有数据库外观的图片)当我尝试显示2张照片时,我只能看到我在数据库中看到的一张照片。这里有什么问题?显示多张照片时出错

HTML代码,上传照片

<input type="file" id="_photo" name="_photo[]" multiple="multiple"> 
<input type="button" id="add_more" class="" value="Add More Files"/> 

代码保存在数据库和文件夹的照片

if (!empty($_FILES['_photo']['name'][$i])) { 
     if ($_FILES['_photo']['type'][$i] == 'image/jpeg') { 
      $upload_folder = "./profile_pix/"; 
      $pic_name = time() . ".jpg"; 
      $pic_path = $upload_folder . $pic_name; 
      require_once "include/resize.php"; 
       if (move_uploaded_file($_FILES['_photo']['tmp_name'][$i], $pic_path)) { 
        $image = new Resize($pic_path); 
        $image->resizeImage(180, 180, 'crop'); 
        $image->saveImage($pic_path); 
        //thumbnail 
        $image = new Resize($pic_path); 
        $image->resizeImage(50, 50, 'crop'); 
        $image->saveImage($upload_folder . "thumb/" . $pic_name); 
       } 
     } 
    } 
    else { 
    $pic_name="default_house.png"; 
    } 
    $sql = "INSERT INTO offers 
       (accommodation, school, date, available, member_id, photo,) 
       VALUES 
       (:accommodation, :school, :date, 'yes', :member_id, '$pic_name',)"; 

$query = $db->($sql, array(..........));  

代码以显示上传的照片

$sql = "SELECT * FROM myDatabase"; 
foreach ($db->query($sql) AS $result){ 
echo " 
<img src='profile_pix/{$result['photos']}' width = '30' height ='30px' style=' margin-top:8px;'/> 
"; 
}enter image description here 
+0

使用foreach还可以将图像链接保存在数据库中 – 2015-03-25 09:32:02

回答

0

尝试以下,希望它会工作。记住你的专栏是photo,而不是photos

<?php 
    $sql = "SELECT * FROM myDatabase"; 
    $sqlres = mysql_query($sql); 
    foreach ($sqlres AS $result){ 
    echo "<img src='profile_pix/".$result['photo']." width = '30' height ='30px' style=' margin-top:8px;'/>"; 
    } 
?>