程序不会根据输入调用正确的功能。不知道我缺少

Question

编辑：在main（）了一下周围玩耍后，它似乎是在程序选择哪个函数被调用的，如果/ elif的块不管输入的。我不知道为什么它开始工作的罚款

我已经看了后在我的代码这样做，我也弄不清是什么，我没有看到。 这是一个数字序列游戏，它要求用户选择简单和困难之间的困难。它在某一点上工作得很好，但现在无论选择什么，每次都会进入简单模式。即使你没有任何输入就直接回车。

#main program function and difficulty selection 
def main(): 
print('-----------------------------------------------') 
print('Please choose a difficulty.') 
difficulty = str(input('(e)asy|(h)ard: ')) 
print('-----------------------------------------------') 
if difficulty == 'easy'or'e': 
    easy() 
elif difficulty == 'hard'or'h': 
    hard() 

然后我有一个简单的功能，一个很难。 硬只是简单的功能，只改变生成的序列的大小，没有别的。我已经浏览了每个模块，没有任何更改会影响哪个函数被调用。

不管它发生了多少次的游戏的玩法，所以它必须是坏了我的main（）函数

的代码的其余部分是在这里有没有什么帮助，也许我失去了一些东西明显。

import random 
def easy(): 
    print ('Easy Mode','\n') 
    #Generates inital number, step value, and upper limit 
    num_sequence = 5 
    numbers = random.randint(1,101) 
    step = random.randint(1,20) 
    #Accumulates and prints all but last number in sequence 
    for num_generated in range (1, num_sequence): 
     print(numbers) 
     numbers = numbers + step 
    #Sets tries allowed and subtracts wrong attempts 
    guesses = 3 
    while guesses > 0: 
     user_num = int(input('Next Number: ')) 
     guesses = guesses - 1 
     if user_num != numbers: 
      if guesses == 0: 
       break 
      else: 
       print('Try Again (Attempts Remaining:', guesses,')')    
     if user_num == numbers: 
      break 

#Prints appropriate message based on game results      
    if user_num == numbers: 
     print ('Correct','\n') 
    if user_num != numbers: 
     print ('Attempts Exceeded: The answer was',numbers,'\n') 

#block for hard difficulty (same as above, sequence size changed to 4) 
def hard(): 
    print ('Hard Mode','\n') 
    num_sequence = 4 

#main program function and difficulty selection 
def main(): 
    print('-----------------------------------------------') 
    print('Please choose a difficulty.') 
    difficulty = str(input('(e)asy|(h)ard: ')) 
    print('-----------------------------------------------') 
    if difficulty == 'easy'or'e': 
     easy() 
    elif difficulty == 'hard'or'h': 
     hard() 

#block for replay selection 
replay = 'y' 
while replay == 'y': 
    main() 
    replay = input('Play again? (y)|(n): ',) 
    print ('\n') 
    if replay == 'n': 
     print('-----------------------------------------------') 
     print('Goodbye!') 
     print('-----------------------------------------------') 
     break 

硬（）是相同的代码的那些前几个

Answer 1

当你制造复合比较（使用或）的条件的双方必须是完整的后线容易（）行。换句话说，

if difficulty == 'easy'or difficulty == 'e': 
    easy() 
elif difficulty == 'hard'or difficulty == 'h': 
    hard() 

否则你说：“如果难度==‘容易’>>这是假的，然后分配给困难‘E’”，这是不是意图。